Indexing Based On Cell Array

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RDG
RDG on 6 Sep 2012
randvar=cell(50,1);
for h=1:50
randvar{h}=zeros(10,4);
randvar{h}(:,1)=randi(10,10,1);
randvar{h}(:,2)=randi(5,10,1);
randvar{h}(:,3)=randi(10,10,1);
randvar{h}(:,4)=randi(17,10,1);
end
for counter=1:15
for h=1:50
a{h}=0;
for i=1:10
for j=1:10-i
if randvar{h}(i,1) ~= randvar{h}(i+j,1)
if randvar{h}(i,2)==randvar{h}(i+j,2)
if randvar{h}(i,3)==randvar{h}(i+j,3)
if randvar{h}(i,4)==randvar{h}(i+j,4)
a{h}=a{h}+10;
else
a{h}=a{h}+0;
end
end
end
end
end
end
end
end
[B, IX] = sortrows(a);
least = randvar(IX(1:10));
I don't quite understand why the IX returns 1. Shouldn't it return all the index of the cell array elements? I want to retrieve the first 10 least value for a for randvar.
P/S: My code works when I'm using cell2mat but because there're many loops, converting from cell2mat and mat2cell doesn't seem to be efficient.
  1 Comment
Andrei Bobrov
Andrei Bobrov on 6 Sep 2012
Edited: Andrei Bobrov on 6 Sep 2012
a = cell(size(randvar));
for jj = 1:numel(a)
x = randvar{jj};
[b b c] = unique(x(:,1),'first');
y = false(size(c));
y(b) = true;
z = x(y,2:end);
[b b c] = unique(z,'first','rows');
q = true(size(c));
q(b) = false;
a{jj} = nnz(q)*10;
end
[IX, IX] = sortrows(a);
least = randvar(IX(1:10));
or code for loop for..end
for h=1:50
a{h}=0;
for i=1:10
for j=1:10-i
if randvar{h}(i,1) ~= randvar{h}(i+j,1)&&...
isequal(randvar{h}(i,2:end),randvar{h}(i+j,2:end))
a{h}=a{h}+10;
end
end
end
end

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Accepted Answer

Arthur
Arthur on 6 Sep 2012
Edited: Arthur on 6 Sep 2012
a is an matrix of 1 row and 50 columns. And like doc sortrow states: "If A is an m-by-n matrix, then B = A(index,:)."
So, initialize a like this, and you're fine:
a = cell(50,1);

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