For loop within for loop

Please help me out. This code isn't working...
qq=8:10008;
for m = 1:9
for n = 1:10001
A(m, n) = (m+n)+qq;
end
end
I just want answer for A

3 comentarios

Adam
Adam el 8 de Ag. de 2019
Editada: Adam el 8 de Ag. de 2019
No idea what answer you want since you didn't tell us and you already said the code isn't working so there's not much point us looking at that to understand what you want.
However, you are adding a vector, qq, to a scalar (m+n) and trying to assign the result of this to a scalar A(m,n) which clearly will not work. At a guess you want to add qq(n) instead.
DARLINGTON ETAJE
DARLINGTON ETAJE el 8 de Ag. de 2019
You just solved the problem...qq(n) works....thank you.
Alex Mcaulley
Alex Mcaulley el 9 de Ag. de 2019
Editada: Alex Mcaulley el 9 de Ag. de 2019
You can do it without loop. For example:
qq = 8:10008;
n = 1:10001;
m = 1:9;
[X,Y] = meshgrid(qq + n,m)
A = X + Y;
If you use the loops, at least preallocate your array A to minimize the execution time:
qq = 8:10008;
A = zeros(9,10001);
for m = 1:9
for n = 1:10001
A(m, n) = (m+n)+qq(n);
end
end

Iniciar sesión para comentar.

Respuestas (1)

Jos (10584)
Jos (10584) el 9 de Ag. de 2019

1 voto

In recent ML versions there is no need for meshgrid or so. The plus syntax will expand the vectors :-)
% a smaller example
n = 1:11
m = 1:4
q = 8:18
A = m' + n + q

Categorías

Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

Etiquetas

Preguntada:

el 8 de Ag. de 2019

Respondida:

el 9 de Ag. de 2019

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by