Combining sub-matrices diagonally within a for loop
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Rengin
el 13 de Ag. de 2019
Comentada: Rengin
el 13 de Ag. de 2019
clear all;
clc;
close all;
n=[3 1 2];
for kk=1:length(n)
matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
val=2*ii+jj;
matrix(ii,jj)=val;
end
end
end
% Dear users, if you put a debug at the very last "end" (row 13), you can
% see that I aim to generate 3 sub-matrices having the size of 3x3, 1x1 and
% 2x2 (see n=[3 1 2]). I want to combine each sub-matrix one each other diagonally.
% I want to get the matrix as a result below:
matrix=[3 4 5 0 0 0;5 6 7 0 0 0;7 8 9 0 0 0;0 0 0 3 0 0;0 0 0 0 3 4;0 0 0 0 5 6];
%Is there any simple way to do it?
%Thanks in advance!
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Respuesta aceptada
Bruno Luong
el 13 de Ag. de 2019
submats = arrayfun(@(n) 2*(1:n)'+(1:n),[3 1 2],'unif',0)
matrix = blkdiag(submats{:})
4 comentarios
Bruno Luong
el 13 de Ag. de 2019
I actually wait to see what do you learn and how you manage to adatp the above code to this tiny change.
Más respuestas (1)
Rengin
el 13 de Ag. de 2019
2 comentarios
Bruno Luong
el 13 de Ag. de 2019
Editada: Bruno Luong
el 13 de Ag. de 2019
n=[3 1 2];
rad=[0.04 0.02 0.01];
h=[10 12 15];
submats = arrayfun(@(n,r,h) r*h*ones(n),n,rad,h,'unif',0);
...
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