# Combination of sub-matrices generated within a for loop

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Rengin on 13 Aug 2019
Commented: Bruno Luong on 13 Aug 2019
clear;
clc;
close all;
n=[3 1 2];
h=[10 12 15];
for kk=1:length(n)
matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
matrix(ii,jj)=val;
end
end
end
% Dear users, if you put a debug at the very last "end" (row 17), you can
% see that I aim to generate 3 sub-matrices having the size of 3x3, 1x1 and
% 2x2 (see n=[3 1 2]). I want to combine each sub-matrix one each other diagonally.
% I want to get the matrix as a result below:
matrix=[0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0.4 0.4 0.4 0 0 0;0 0 0 0.24 0 0;0 0 0 0 0.15 0.15;0 0 0 0 0.15 0.15];
%Is there any simple way to do it?

madhan ravi on 13 Aug 2019
madhan ravi on 13 Aug 2019
Bruno Luong on 13 Aug 2019
"The calculation of Val is different."
You might try to learn deeper how computer programming actually works, if you get stuck everytime the values change then you miss the whole purpose of programming.

infinity on 13 Aug 2019
Hello,
There are various solutions for this question, one of the closet one to your current code could be
clear;
clc;
close all;
n=[3 1 2];
h=[10 12 15];
matrix = zeros(sum(n));
for kk=1:length(n)
% matrix=zeros(n(kk),n(kk));
for ii=1:n(kk)
for jj=1:n(kk)
matrix(ii+sum(n(1:kk-1)),jj+sum(n(1:kk-1)))=val;
end
end
end