fix the soulation pleaase
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Please any one can fix this for me please
>> [x,y]=meshgrid(-pi:0.1:pi,-pi:0.1:pi);
>> z=exp(-x.^2*y.^2).*sin(x*y);
>> mesh(x,y,z); axis image;
>> options= {,'interpreter','latex','fontSize',14}; % Use LATEX for labeling
>> xlabel('$x$-axis',options{:}); ylabel('$y$-axis',options{:});
>> title('ASCENT',options{:});
>> hold on
>> p=[-1.6,-1.6];
>> plot(p(1,1),p(1,2),'or','MarkerSize',10);
>> x=p(1,size(p,2));
>> y=p(2,size(p,2));
Index in position 1 exceeds array bounds (must not exceed 1).
>> y=p(1,size(p,2));
>> fx=-2*x*y^2*exp(-x^2*y^2)*sin(x*y);
>> fy= -2*x^2*y*exp(-x^2*y^2)*sin(x*y);
>> p=[p p(:,size(p,2))+0.2*[fx;fy]]; % the only line that really maters
Error using horzcat
Dimensions of arrays being concatenated are not consistent.
1 comentario
Walter Roberson
el 12 de Sept. de 2019
I already explained this to you.
You need to decide whether your y coordinates are to be stored in the second column of the variable, or in the second row of the variable.
Respuestas (1)
Devineni Aslesha
el 12 de Sept. de 2019
In the provided code, the size of p is 1x2. However, the size of p(:,size(p,2))+0.2*[fx;fy] is 2x1. While concatenating horizontally, all the arrays should have the same number of rows. So, it can be concatenated as shown below.
p = [p p(: , size(p,2))+0.2*[fx fy]];
Doc Link:
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