Integrate for a specific period of time

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Allison Bushman
Allison Bushman el 12 de Sept. de 2019
Respondida: Torsten el 13 de Sept. de 2019
Please help me. I am trying to use Euler integration to integrate for 10 seconds with a step size of .01 seconds. Plot x versus time.
x(0) = 1
t=0:.01:10;
x0=1;
xdot=-2*(x^3)+sin(0.5*t)*x;
for t=0:0.01:10
x=integrate(xdot,t,x0);
end
plot(t,x)
  2 comentarios
Walter Roberson
Walter Roberson el 13 de Sept. de 2019
However you do not have a differential equation, so it is not obvious to me what Euler integration would have to do with the situation.
Allison Bushman
Allison Bushman el 13 de Sept. de 2019
xdot is dx/dt

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Respuesta aceptada

Torsten
Torsten el 13 de Sept. de 2019
t=0:.01:10;
x = zeros(numel(t));
x(1) = 1;
fun_xdot = @(t,x) -2*(x^3) + sin(0.5*t)*x;
for i = 1:numel(t)-1
x(i+1) = x(i) + (t(i+1)-t(i))*fun_xdot(t(i),x(i));
end
plot(t,x)

Más respuestas (1)

Robert U
Robert U el 13 de Sept. de 2019
Editada: Robert U el 13 de Sept. de 2019
Hi Allison,
you can use one of Matlab's integrated ODE solvers to solve your differential equation. The code below makes use of ode45.
t=0:.01:10; % explicit time vector
x0=1; % boundary condition
% define function containing my ODE
myODE = @(t,x) -2 .* x^3 + sin( 0.5 .* t) .* x;
% solve ODE with ode45
[tsol,xsol] = ode45(myODE,t,x0);
% plot result as explicit solution points
plot(tsol,xsol,'.')
Kind regards,
Robert

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