which quantile value is good for prediction ?

3 visualizaciones (últimos 30 días)
Hamza Ali
Hamza Ali el 23 de Sept. de 2019
Editada: Hamza Ali el 26 de Sept. de 2019
Hello,
Quantile random forest model is used to predict 1 year solar radiation.
Question : which quantile value should i use to have accurate forecasts ?
Thank you.
  4 comentarios
Adam Danz
Adam Danz el 25 de Sept. de 2019
I'm not familiar with RF or QRF but in terms of expected values from a distribution, the 50 quantile is the median and if the distribution is even remotely normal, then the median is the expected value. If the distribution is not approximately normal then more info is needed in terms of estimating the expected value.
I agree with the cyclist that such a comparison is certainly not a proof in the formal definition of the term. For random processes, bootstrapping is often a good approach at computing expected value and it's error (confidence intervals). But I have no idea if this suggestion is applicable to your project.
Hamza Ali
Hamza Ali el 26 de Sept. de 2019
Editada: Hamza Ali el 26 de Sept. de 2019
Thank you for your answer.
I think that the distribution is non-parametric distribution (see the figure below). In fact, the recent litterature in this field, shows the superiority of QRF compared to RF in terms of forecasting accuracy.
I wanted to say that if it is a proof in the experimental sense, because i found in research articles that authors try different values of quantiles (0.1: 0.1: 0.9), anf they choose the quantile that gives small error.
I wonder if this experimental technique is valid to demonstrate why we have choosen the quantile value ?

Iniciar sesión para comentar.

Respuesta aceptada

the cyclist
the cyclist el 23 de Sept. de 2019
The usual random forest (RF) algorithm gives a point estimate for each set of input values. It predicts one value.
The point of quantile random forest (QRF) is to provide an estimate of the dispersion of observations around the predicted value.
So, if all you care about is the prediction value, you don't really need to use QRF; you could just use RF. That being said, I expect the 50th percentile gives the best average prediction.
  2 comentarios
Hamza Ali
Hamza Ali el 25 de Sept. de 2019
Thank you for your answer.
In fact, i have compred between RF and QRF(0.5) algorithms, and the result shows that QRF model outperforms RF in term of mse. In addition, different values of quantiles [0.05 0.1 0.25 0.5 0.75 0.9 0.95] have been used to determine the best quantile. the best quantile that gives low error is the 50th percentile as you said.
Question : This comparaison, between different values of quantiles, is sufficient to prove that 50th quantile (or other quantile) should be used to have accurate forecasts ?
Thank you.
the cyclist
the cyclist el 25 de Sept. de 2019
It is certainly not proof (in the mathematical sense). I suppose it is evidence.
I am not an expert in QRF, but my understanding is that its primary purpose is to get a sense of variability around the point estimate. So, I am not really sure of what you are trying to do here. (Unless it is just a homework problem, as Adam has speculated.)

Iniciar sesión para comentar.

Más respuestas (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by