Cut a matrix after a certain value

Given the following matrix

Acum=[116.200000000000	237.300000000000	329.300000000000	391.200000000000	561	                619.900000000000	719.900000000000	785.900000000000	902.900000000000	967.900000000000	1022.90000000000;
174.200000000000	342.600000000000	429.100000000000	513.600000000000	781.800000000000	845.600000000000	945.600000000000	1011.60000000000	1128.60000000000	1193.60000000000	1248.60000000000;
232.300000000000	432.200000000000	523.000000000000	584.900000000000	912.100000000000	971.000000000000	1071	                1137	                1254	                1319	                1374;
290.400000000000	521.800000000000	613.800000000000	675.700000000000	1042.40000000000	1101.30000000000	1201.30000000000	1267.30000000000	1384.30000000000	1449.30000000000	1504.30000000000;
348.500000000000	611.400000000000	704.600000000000	766.500000000000	1172.70000000000	1231.60000000000	1331.60000000000	1397.60000000000	1514.60000000000	1579.60000000000	1634.60000000000;
406.600000000000	701	                795.400000000000	857.300000000000	1303.00000000000	1361.90000000000	1461.90000000000	1527.90000000000	1644.90000000000	1709.90000000000	1764.90000000000;
464.600000000000	806.300000000000	892.800000000000	977.300000000000	1523.80000000000	1587.60000000000	1687.60000000000	1753.60000000000	1870.60000000000	1935.60000000000	1990.60000000000;
522.600000000000	911.600000000000	998.100000000000	1082.60000000000	1744.60000000000	1808.40000000000	1908.40000000000	1974.40000000000	2091.40000000000	2156.40000000000	2211.40000000000;
580.700000000000	1001.20000000000	1092	                1153.90000000000	1874.90000000000	1933.80000000000	2033.80000000000	2099.80000000000	2216.80000000000	2281.80000000000	2336.80000000000;
638.800000000000	1090.80000000000	1182.80000000000	1244.70000000000	2005.20000000000	2064.10000000000	2164.10000000000	2230.10000000000	2347.10000000000	2412.10000000000	2467.10000000000;
696.900000000000	1180.40000000000	1273.60000000000	1335.50000000000	2135.50000000000	2194.40000000000	2294.40000000000	2360.40000000000	2477.40000000000	2542.40000000000	2597.40000000000;
754.900000000000	1285.70000000000	1372.20000000000	1456.70000000000	2356.30000000000	2420.10000000000	2520.10000000000	2586.10000000000	2703.10000000000	2768.10000000000	2823.10000000000;
812.900000000000	1391.00000000000	1477.50000000000	1562.00000000000	2577.10000000000	2640.90000000000	2740.90000000000	2806.90000000000	2923.90000000000	2988.90000000000	3043.90000000000;
870.900000000000	1496.30000000000	1582.80000000000	1667.30000000000	2797.90000000000	2861.70000000000	2961.70000000000	3027.70000000000	3144.70000000000	3209.70000000000	3264.70000000000;
929.000000000000	1585.90000000000	1676.70000000000	1738.60000000000	2928.20000000000	2987.10000000000	3087.10000000000	3153.10000000000	3270.10000000000	3335.10000000000	3390.10000000000]

With the code

 rowNum = find(any(Acum > 2500,2),1,'first'); % 1440*60= 86400 secondi. è il tempo disponibile nella giornata
 CUM=Acum(1:rowNum-1,:);

I want to cut the matrix as soon as I meet a value > 2500.

Till here it's all right. But if the matrix contain all the values < 2500. "rowNum" doesn't exist and I cannot find CUM, while instead if rownum doesn't exist is simply CUM=Acum.

For example, considering

 Acum1=[116.200000000000	237.300000000000	329.300000000000	391.200000000000	561	                619.900000000000	719.900000000000	785.900000000000	902.900000000000	967.900000000000	1022.90000000000;
174.200000000000	342.600000000000	429.100000000000	513.600000000000	781.800000000000	845.600000000000	945.600000000000	1011.60000000000	1128.60000000000	1193.60000000000	1248.60000000000;
232.300000000000	432.200000000000	523.000000000000	584.900000000000	912.100000000000	971.000000000000	1071	                1137	                1254	                1319	                1374;
290.400000000000	521.800000000000	613.800000000000	675.700000000000	1042.40000000000	1101.30000000000	1201.30000000000	1267.30000000000	1384.30000000000	1449.30000000000	1504.30000000000;
348.500000000000	611.400000000000	704.600000000000	766.500000000000	1172.70000000000	1231.60000000000	1331.60000000000	1397.60000000000	1514.60000000000	1579.60000000000	1634.60000000000;
406.600000000000	701	                795.400000000000	857.300000000000	1303.00000000000	1361.90000000000	1461.90000000000	1527.90000000000	1644.90000000000	1709.90000000000	1764.90000000000;
464.600000000000	806.300000000000	892.800000000000	977.300000000000	1523.80000000000	1587.60000000000	1687.60000000000	1753.60000000000	1870.60000000000	1935.60000000000	1990.60000000000;
522.600000000000	911.600000000000	998.100000000000	1082.60000000000	1744.60000000000	1808.40000000000	1908.40000000000	1974.40000000000	2091.40000000000	2156.40000000000	2211.40000000000]

the code

rowNum = find(any(Acum1 > 2500,2),1,'first'); % 1440*60= 86400 secondi. è il tempo disponibile nella giornata
CUM=Acum1(1:rowNum-1,:);

give me an empty matrix CUM.

May someone help me to construct a code that coinsider both the options?

thanks

Answer 1

[Bjorn Gustavsson]

Try:

rowNum = find(any(Acum1 > 2500,2),1,'first'); % 1440*60= 86400 secondi. è il tempo disponibile nella giornata
if isempty(rowNum)
  CUM = Acum;  
else
  CUM = Acum1(1:rowNum-1,:);
end

HTH