for loop that changes specific letters to numbers

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Seaturtle
Seaturtle el 2 de Oct. de 2019
Comentada: Adam Danz el 4 de Oct. de 2019
I want to replace the vowels AEIOU with the number 0 and all other letters with the number 1. For example the output should be ans = [0 1 1 1 0] if the user inputs apple. I know I must be misunderstanding how to get the loop to go through my whole string. This is what I have managed so far.
party = input('What is your answer? ', 's');
n = length(party)
for i = 1:n
if i == 'A'
disp(0)
elseif i == 'B'
disp(1)
elseif i == 'C'
disp(1)
end
end

Respuesta aceptada

Walter Roberson
Walter Roberson el 2 de Oct. de 2019
party = input('What is your answer? ', 's');
n = length(party)
for i = 1:n
if party(i) == 'A'
party(i) = 0;
elseif i == 'B'
party(i) = 1;
elseif i == 'C'
party(i) = 1;
end
end
disp( double(party) )
  7 comentarios
Guillaume
Guillaume el 3 de Oct. de 2019
It would be nice if 'vowel' were a category option.
The problem with that is what is a vowel or not depends on the language. Some letters such as 'y' in english can also qualify as a vowel or consonant depending on the word.
Adam Danz
Adam Danz el 3 de Oct. de 2019
True. It would be neat to play around with one of the vowel classification algorithms that are not specific to any language such as this one (link below) that is based on character co-occurrences. It wouldn't necessarily solve the fuzzy set problem but it would be a semi-objective, language-independent classification.

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Más respuestas (2)

Adam Danz
Adam Danz el 2 de Oct. de 2019
Editada: Adam Danz el 2 de Oct. de 2019
No loop needed.
str = 'apple';
isConsonant = ~ismember(lower(str),'aeiou') %lower() makes it not case sensitive
If you really wanted to do that in a loop,
n = numel(party);
isConsonant = true(1,n);
for i = 1:n
if ismember(party(i),'aeiou')
isConsonant(i) = false;
end
end
In both cases, isConsonant is a logical vector. If you want a double vector of 0/1 instead of false/true,
isConsonant = double(isConsonant);
  8 comentarios
Seaturtle
Seaturtle el 3 de Oct. de 2019
Editada: Seaturtle el 3 de Oct. de 2019
Thanks for this answer! This really helped with my understanding of not using a loop to do something with shorter code.
Adam Danz
Adam Danz el 3 de Oct. de 2019
Glad I could chip in! :)

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Jos (10584)
Jos (10584) el 3 de Oct. de 2019
Another option:
str = 'apple';
TF1 = any(lower(str) ~= 'aeiou'.')
  6 comentarios
Jos (10584)
Jos (10584) el 4 de Oct. de 2019
Thanks for the corrections :-)
Adam Danz
Adam Danz el 4 de Oct. de 2019
+1
This implicit expansion solution is faster and neater than my ismember() solution.

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