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Why is this not outputting anything?

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Hunter Steele
Hunter Steele on 9 Oct 2019
Edited: Adam Danz on 9 Oct 2019
function output = MyMin(x)
MIN_VALUE=0;
[m, n]=size(x);
for i=1:length(x)
if MIN_VALUE>x(i)
MIN_VALUE=x(i);
index=i;
output = [MIN_VALUE, index];
end
end

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Accepted Answer

meghannmarie
meghannmarie on 9 Oct 2019
Edited: meghannmarie on 9 Oct 2019
For this to work you need to set your intial MIN_VALUE to inf rather than 0. If its set to zero, it will only make output if you send it a negative number, otherwise it will never go into that if statement.
function output = MyMin(x)
MIN_VALUE=inf;
for i=1:length(x)
if MIN_VALUE>x(i)
MIN_VALUE=x(i);
index=i;
output = [MIN_VALUE, index];
end
end
end

  2 Comments

Hunter Steele
Hunter Steele on 9 Oct 2019
Thank you for making that clear!
Adam Danz
Adam Danz on 9 Oct 2019
I didn't see meghannmarie's answer, before posting mine (minutes apart). I just wanted to add that the min() function does what you're loop is doing and it's a lot more efficient.
[MIN_VALUE, index] = min(x);
The only difference is that the min() function splits the output into two while yours reutrns a 1x2 vector.

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