obtain a matrix out of other matrix

Hello

I have a 1*104 matrix which ı have to create a 8*13 matrix out of it.

For one column of the final 8*13 matrix I can do the following code but how can I write one single code to get the whole matrix

zs_d=zeros(8,1);
for r=1:8;
zs_d(8,1)=(zs(13*r-12));
end 

This gives me the first coloumn and for the second column I can write :

for r=1:8;
zs_d(8,1)=(zs(13*r-11));
end 

and it goes the same till end...

I tried to write it in one for loop like the following but it gave me an error:

zs_d=zeros(8,13);
for r=1:8,c=1:12;
zs_d(8,13)=(zs(13*r-13-c));
end 

error : Subscript indices must either be real positive integers or logicals.

thanks for the help

[Fangjun Jiang]

Your code does not match your description. In any case, I think reshape() should help you.

[mehra]

Maybe I can add that my 104*1 matrix is zs and I need to get zs(1), zs(14) , zs(27), zs(40), zs(53),zs(66),zs(79),zs(92) in the first column and the rest will also follow the trend to be in the 2nd to 13th columns. Please let me know if any other explanation is needed.

Answer 1

[Fangjun Jiang]

transpose(reshape((1:104)',13,[]))

Answer 2

[Steven Lord]

reshape your vector to be 13-by-8 then take the transpose of it.

>> x = 1:104;
>> y = reshape(x, [13 8])
>> z = y.'

You can do this in one step, but I think it's important to see the intermediate result (y) so you can see how MATLAB arranges elements. This is useful knowledge for a technique called linear indexing.

[mehra]

thanks alot