Creating permutations of vectors using basic matlab commands such as loops.
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In the problem I have to take a vector x = [x1,x2,x3,x4] ,where 0 <= xi <= m, and m is an inputted integer.
For example if m = 1,
I would need to create vectors
[0,0,0,0]
[1,0,0,0]
[0,1,0,0]
[0,0,1,0]
[0,0,0,1]
[1,1,0,0]
all the way to [1,1,1,1]
2 comentarios
Do you have a specific question? What have you tried so far? Also, here is a cheeky way of getting your result:
M = dec2bin(0:15)-'0'; % where 15 is length(x)^2-1
cody madsen
el 28 de Oct. de 2019
Editada: cody madsen
el 28 de Oct. de 2019
Respuestas (1)
Daniel M
el 28 de Oct. de 2019
You can do it in two lines of code by using ndgrid, and putting the four outputs column-wise into a matrix. That would be the most efficient way. If you're required to use loops, that is lame.
[a,b,c,d] = ndgrid(0:4);
M = [d(:) c(:) b(:) a(:)];
4 comentarios
cody madsen
el 28 de Oct. de 2019
Daniel M
el 28 de Oct. de 2019
I highly doubt you're required to store each vector separately. That would be 625 variables. And how are you supposed to utilize 625 variables in a subsequent loop, with 625 different names? As opposed to using one variable, M above, and looping over the rows of it.
cody madsen
el 28 de Oct. de 2019
Daniel M
el 28 de Oct. de 2019
Right, but all the vectors would be stored as rows in the matrix T. We're saying the same thing. As for your algorithm, start by calculating how many iterations you'll need, given N number of elements and M number of spots. E.g. you already know for N = 5 (from 0:4) and M = 4 the number of rows of T is 625. But how is that calculated?
Then start very simply using only M = 2 and N = 2, and see if you can code that properly.
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