Function of vector with letter grade

function [A, B, C, D, E, F] = grade(value)

end

I want to make a letter note calculation using vector, but it shows only one number in the code I write, it works when I enter the number (90) but [(70,89,100]) how can I do if I can't get results in numbers?

[Ruger28]

What did you try so far?

[Daniel M]

It would probably make more sense to return a cellstring same length as values containing the letter grade as a char.

[Ruger28]

You said you had something, so what have you tried? No one is going to do it for you.

[John D'Errico]

Please don't use answers just to make a plea for help. You need to show what you are doing, as otherwise, we are just doing your work and thinking for you. You learn nothing then.

[Adam Danz]

In order to better describe the problem, you could provide some input-output pairs that would show what the function is supposed to be doing. For example, one interpretation of your question would be that your input is a vector of percentage grades and your output is a single letter grade in the form of a chracter ('A') or a string ("A"). Another interpretation would be that your input is a vectof of percentage grades and your output is an array of strings/chars in the form {'A','B','F'} or ["A","B","F"].

By showing us what you've already tried (suggested above) we would get a better understanding of what you're trying to do and where that's going wrong.

More important lesson here: Proposing a solution to this problem would probably just take a few seconds and 1 line of code but there has already been 6 hours since the first comment to this problem and 4 different people chipping in. That's because the problem is not well defined.

"If I had only one hour to save the world, I would spend fifty-five minutes defining the problem, and only five minutes finding the solution." -Albert Einstein

[Howart Stan]

This is the code I wrote but I can't do it anymore I'm getting an error now

function [A, B, C, D, E, F] = fun_degree(inp)

if inp >=90 && inp >=100
 [A, B, C, D, E, F]='A';
elseif inp >=89 && inp >= 80
 [A, B, C, D, E, F]='B';
elseif inp >=79 && inp >=70
 [A, B, C, D, E, F]='C';
elseif inp >=69 && inp >=60
 [A, B, C, D, E, F]='D';
elseif inp >=59 && inp >=50
 [A, B, C, D, E, F]='E';
elseif inp <50
[A, B, C, D, E, F]='F';
end
end

[Adam Danz]

As the error message indicates, you cannot assign a character (or any scalar) to a vector of outputs.

I asked about what your inputs look like but you didn't reply to that question.

[Howart Stan]

A=[100:90]

B=[89:80]

C=[79:70]

D=[69:60]

E=[59:50]

F=[49:0]

the program I want to do for example [52, 81, 82, 90, 15, 92, 42] when i write these numbers

a=

90 92

b=

81 82

c= empty matrix

d= empty matrix

e=

52

f=

15 42

[Adam Danz]

@Howart Stan, the bigger lesson to be learned here is to clearly define your problem before volunteers start working on it ;)

See my updated answer (at the bottom).

[Howart Stan]

function [A, B, C, D, E, F] = fun_degree(x)
[a,b,c,d,e,f]=y(x);
if a >=90
    A='A';
elseif b >=80
    B='B';
elseif c >=70
    C='C';
elseif d >=60
    D='D';
elseif e >=50
    E='E';
elseif  f < 50
    F='F';
    

end
end

Error in fun_degree (line 2)

[a,b,c,d,e,f]=deger(inp);

I want to write in this format but I got an error like this. What could be the reason?

Also thank you for help

[Adam Danz]

If that's the form you want, then follow Sulaymon Eshkabilov's example.

Answer 1

[Adam Danz]

Here, you can enter any type of numeric input from scalars, vectors, matricies, to n-dimensional arrays and the output will be the same shape.

function GRADE = fun_degree(inp)
    grp = discretize(inp,[-inf,50:10:90,inf]);
    letters = {'F' 'E' 'D' 'C' 'B' 'A'};
    GRADE = letters(grp);
end

Test it...

inp = [0:10:100, 22 33 44 55 66 77 88 99] % 1 x 19 vector
GRADE = fun_degree(inp)
% {'F'}    {'F'}    {'F'}    {'F'}    {'F'}    {'E'}    {'D'}    {'C'}    {'B'}    {'A'}   . . . . .



inp = reshape(45:100, 7,8); % 7 x 8 matrix
GRADE = fun_degree(inp)
% GRADE =
%   7×8 cell array
%     {'F'}    {'E'}    {'E'}    {'D'}    {'C'}    {'B'}    {'B'}    {'A'}
%     {'F'}    {'E'}    {'D'}    {'D'}    {'C'}    {'B'}    {'B'}    {'A'}
%     {'F'}    {'E'}    {'D'}    {'D'}    {'C'}    {'B'}    {'B'}    {'A'}
%     {'F'}    {'E'}    {'D'}    {'D'}    {'C'}    {'B'}    {'A'}    {'A'}
%     {'F'}    {'E'}    {'D'}    {'C'}    {'C'}    {'B'}    {'A'}    {'A'}
%     {'E'}    {'E'}    {'D'}    {'C'}    {'C'}    {'B'}    {'A'}    {'A'}
%     {'E'}    {'E'}    {'D'}    {'C'}    {'C'}    {'B'}    {'A'}    {'A'}



inp = 98.5; 
GRADE = fun_degree(inp)
% GRADE =
%   1×1 cell array
%    {'A'}               %Cell array
GRADE = GRADE{:}; 
% GRADE =
%     'A'                % Char

[addendum]

Here's the modified function to output the number of As, Bs, etc...

function [A, B, C, D, E, F, GRADE] = fun_degree(inp)
    grp = discretize(inp,[-inf,50:10:90,inf]);
    letters = {'F' 'E' 'D' 'C' 'B' 'A'};
    GRADE = letters(grp);
    F = sum(grp(:)==1); 
    E = sum(grp(:)==2); 
    D = sum(grp(:)==3); 
    C = sum(grp(:)==4); 
    B = sum(grp(:)==5); 
    A = sum(grp(:)==6); 
end

Answer 2

[Sulaymon Eshkabilov]

Hi,

function GRADE = fun_degree(inp)
if inp >=90 
 GRADE='A';
 fprintf('Your score is %d and Your earned grade is A \n', inp)
elseif inp <90 && inp >= 80
 GRADE='B';
 fprintf('Your score is %d and Your earned grade is B \n', inp)
elseif inp <80 && inp >=70
 GRADE='C';
 fprintf('Your score is %d and Your earned grade is C \n', inp)
elseif inp <70 && inp >=60
 GRADE='D';
 fprintf('Your score is %d and Your earned grade is D \n', inp)
elseif inp <60 && inp >=50
 GRADE='E';
 fprintf('Your score is %d and Your earned grade is E \n', inp)
else % inp <50
GRADE='F';
fprintf('Your score is %d and Your earned grade is F. Sorry you have failed :( \n', inp)
end
end

A shorter version as mentioned:

function GRADE = fun_degree(inp)
if inp >=90 
 GRADE='A';
 elseif inp <90 && inp >= 80
 GRADE='B';
elseif inp <80 && inp >=70
 GRADE='C';
 elseif inp <70 && inp >=60
 GRADE='D';
 elseif inp <60 && inp >=50
 GRADE='E';
 else % inp <50
GRADE='F';
end
fprintf('Your score is %2.2f and Your earned grade is %c \n', inp, GRADE)
end

Good luck.

[Adam Danz]

The update is much better. This output might be cleaner

fprintf('Your score is %.3g and Your earned grade is %c \n', inp, GRADE)
%                      ^^^^

Compare:

Your score is 89.5 and Your earned grade is B             % with %.3g
Your score is 8.950000e+01 and Your earned grade is B     % with %d