# Line, column, and value in matrix B of repeated values ​​in A.

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Ricardo Gutierrez el 7 de Nov. de 2019
Comentada: Ricardo Gutierrez el 8 de Nov. de 2019
Hi. Good day.
I have a code that indicates line, column and value in matrix B, which are in vector A.
But this code does not allow me to have repeated values ​​in matrix B, which is already in vector A
% ________________________________
clc; clear; close all; format short;
A = [10 8 8 6 2];
B = [10 12 16 15 11
8 16 21 6 26
85 61 21 48 11
41 52 62 44 2
29 51 55 59 16
98 95 93 92 99];

for b = 1: 1: 5
Value (b) = A (1, b);
[row (b), col (b)] = find (B == Value (b));
end
Value
row
col
=========================================
Command Window
Value =
10 8 8 6 2
row =
1 2 2 2 4
col =
1 1 1 4 5
===========================================
What do I have to do to make the code detect the position of repeated values ​​in matrix B
Something like that:
A = [10 8 8 6 2];

B = [10 12 16 15 11
8 16 21 6 26
8 61 21 48 11
41 52 62 44 2
29 51 55 59 16
98 95 93 92 99];
Command Window
Value =
10 8 8 6 2
row =
1 2 3 2 4
col =
1 1 1 4 5
----------------------------
Hoping you can help me.
Thank you.
##### 2 comentariosMostrar NingunoOcultar Ninguno
per isakson el 7 de Nov. de 2019
Is it true that
• a value that is repeated in A must be repeated the same number of times in B ?
• repeated values in A are consecutive
Ricardo Gutierrez el 8 de Nov. de 2019
A value that is repeated in A must be repeated the same number of times in B? ==== Yes
Repeated values in A are consecutive ===== Yes
In fact the vector A by a mathematical process was formed by data of the matrix B therefore the values in A must be in B.

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JESUS DAVID ARIZA ROYETH el 8 de Nov. de 2019
solution :
[row,col]=find(ismember(B,A))
##### 1 comentarioMostrar -1 comentarios más antiguosOcultar -1 comentarios más antiguos
Ricardo Gutierrez el 8 de Nov. de 2019
Excelente !!!!!!
Funciono.

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