Surface area of sphere integral form

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Riley Copeland
Riley Copeland el 8 de Nov. de 2019
Editada: Shubham Gupta el 8 de Nov. de 2019
I want to write a section of code that calculates the surface area of a sphere by solving the integral form. The ultimate goal is to change the limits of integration to find sections of the area. Problem is that the value of 'S' I'm getting is way off. Thanks for the help!
R = 1; % radius of sphere (m)
theta_1 = 0;
theta_2 = pi;
fun = @(theta) -cos(theta);
S = 4*pi*R^2*(integral(fun,theta_1,theta_2));

Respuestas (1)

Shubham Gupta
Shubham Gupta el 8 de Nov. de 2019
Editada: Shubham Gupta el 8 de Nov. de 2019
Limits should be [0, pi/2] & fun should be sin
fun = @(theta) sin(theta);
S = 4*pi*R^2*(integral(fun,theta_1,theta_2/2)); % this will give correct answer

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