Remove a number and its duplicates, not just the repeated values i.e. the way the unique function operates

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Vance Blake el 13 de Nov. de 2019
Editada: Vance Blake el 24 de En. de 2020
Hi, I am trying to remove both the number itself and its duplicates from my matrix. For example if A was the matrix (column vector in this case but could be a matrix in the future) shown below, I wish to remove all the 2's and 3's from it, but unique(A); would just remove the second 2 and 3 respectively. I use this matrix as an example but it could be any number that is duplicated any number of times. I would like to remove both the number and its repeats from the matrix (vector). Thanks for all tips and information. Lemme know if any clarification is needed.
A = [2;2;4;3;3;5;6];
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Vance Blake el 13 de Nov. de 2019
Editada: Vance Blake el 24 de En. de 2020
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Más respuestas (1)

Thomas Satterly el 13 de Nov. de 2019
This should lead you along the right track:
% Ex:
% A = [2;2;4;3;3;5;6];
% remove(A, 2) Removes all 2's
% remove(A, 2, 3) Removes all 2's and 3's
function x = remove(x, varargin)
if sum(size(x) > 1) > 1
% Matrix, cannot just "remove" indecies without it being converted
% into an array
for i = 1:numel(varargin)
x(x == varargin{i}) = nan;
end
else
% It's an array, so we can remove indecies and the array will just
% get shorter
for i = 1:numel(varargin)
x(x == varargin{i}) = [];
end
end
end
You can't simply remove data at any index from a matrix and still have a matrix because the matrix dimensions must be preserved. If you do attempt to do this, the matrix will be converted into an array. You can, however, remove entire dimensions from a matrix, e.g. to remove a row from matrix B:
B = rand(3, 5);
B(2, :) = []; % Removes the second row
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Vance Blake el 13 de Nov. de 2019
Hey thanks for the suggestion but I found a related link that came up when I posted my question that solved my problem. Thanks again tho.

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