Can I pass fitobject as a variable to a function

I have curve fit my data using the fit command as given below
[cfit,gof,output] = fit(x,y,fitType)
Now my fitobject is in cfit.
Can I pass this fit object (cfit) as a variable to a function for using the lsqnonlin optimization function
X=___;
Y=___;
[cfit,gof,output] = fit(x,y,fitType)
P0=[ ];%Initial estimation
a=__;%variable
b=__;%variable
lb=[_,...,_];%Lower bound
ub=[_,...,_];%Upper bound
[Widths,resnorm,res,eflag,output1] = lsqnonlin(@(P) function(P,a,b,cfit), P0, lb, ub,options);
%%Function definition
[ ]=function(r,a,b,cfit)
{
fit_result=cfit(r); %for finding the values using fitobject
}
end
Please suggest me know if there is any possiblity for doing this

 Respuesta aceptada

Kavya Vuriti
Kavya Vuriti el 17 de En. de 2020
Hi,
It is possible to pass cfit object directly to lsqnonlin function.
[Widths,resnorm,res,eflag,output1] = lsqnonlin(cfit, P0, lb, ub,options);

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R2019b

Preguntada:

el 18 de Nov. de 2019

Comentada:

el 12 de Abr. de 2020

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