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Help with a double series?

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DIANA CARTLON
DIANA CARTLON on 28 Nov 2019
Commented: Walter Roberson on 18 Apr 2021
I am trying to write function for the equation, can someone tell me what i am doing wrong
clear,clc
a=input('Please enter the dimension, a\n');
b=input('Please enter the dimension, b\n');
h=input('Please enter the thickness, h\n');
E=input('Please enter the Modulus of Eleasticity, E\n');
v=input('Please enter the Poisson Ratio, v\n');
P=input('Please enter the Load, P\n');
xo=input('Please enter the Position, xo\n');
yo=input('Please enter the Position, yo\n');
rec_plate_pt(a,b,P,xo,yo,x,y);
D=(E*h^3)/(12*(1-v^2))
c=(4*P)/(pi^4*a*b*D)
function w = rec_plate_pt(a,b,P,xo,yo,x,y)
s=0;
for m=1:Inf
for n=1:Inf
s=c*(sin((m*pi*xo)/a)*sin((n*pi*yo)/b)/((m^2/a^2+n^2/b^2).^2)*(sin((m*pi*x)/a))*(sin(n*pi*y)/b))
format long
fprintf('%d',w);
end
end
end
  1 Comment
Walter Roberson
Walter Roberson on 28 Nov 2019
Those are infinite series. You should use symsum()

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Answers (2)

Jyothis Gireesh
Jyothis Gireesh on 30 Dec 2019
As Walter mentioned in the previous comment the double summation may be implemented using a combination of symbolic variables and the symsum()” in MATLAB instead of defining a function.
One possible implementation is given below
syms Wc(x,y) m n;
Wc(x,y) = c*symsum(symsum(sin(m*pi*x0/a)*sin(n*pi*y0/b)*sin(m*pi*x/a)*sin(n*pi*y/b)/(m^2/a^2 + n^2/b^2)^2,n,1,Inf),m,1,Inf);

Johannes Ebert
Johannes Ebert on 18 Apr 2021
Hello together,
I have a question: if I apply the code above with my parameter set, the result is the following:
My Input: Wc(120,200)
The result:
(7312256873090709*symsum(symsum(((exp(-(pi*n*10i)/31)*1i)/2 - (exp((pi*n*10i)/31)*1i)/2)^2/(m^2/722500 + n^2/384400)^2, n, 1, Inf)*((exp(-(pi*m*12i)/85)*1i)/2 - (exp((pi*m*12i)/85)*1i)/2)^2, m, 1, Inf))/39614081257132168796771975168
Is there a chance to get the concret value for the used parameter set?
Thanks und kind regards,
Johannes
  3 Comments
Walter Roberson
Walter Roberson on 18 Apr 2021
Maple is able to find an explicit formula for part2 (that is, the inner symsum() ) in terms of a fair number of psi() calls and some trig terms. But it struggles to find anything definite further than that or to simplify the mess.

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