Borrar filtros
Borrar filtros

How to find the symmetry axis of an Image?

8 visualizaciones (últimos 30 días)
Richa Nayak
Richa Nayak el 30 de Sept. de 2012
The image is rotated 60 degrees, gray scale*,.tiff format*. I want find its symmetry axis to rotate it to 0 degrees. I am using MATLAB R2010

Respuestas (2)

Matt J
Matt J el 30 de Sept. de 2012
Assuming you have the Image Processing toolbox, you could use REGIONPROPS(...,'Orientation').

Image Analyst
Image Analyst el 30 de Sept. de 2012
Editada: Image Analyst el 30 de Sept. de 2012
If you have a recent (R2012a or later, I think) Image Processing Toolbox, you can use imregister(). See their example on http://www.mathworks.com/help/images/ref/imregister.html - it does just that.
  5 comentarios
Image Analyst
Image Analyst el 3 de Oct. de 2012
Editada: Image Analyst el 3 de Oct. de 2012
I'm not quite sure how regionprops could be used. Could you give a short demo? To take into account the entire image, the binary image (or labeled image) would have to be the entire image, and then the orientation would not be different for different images because the binary image would be the same for all images. Perhaps I'm just overlooking something.
Matt J
Matt J el 3 de Oct. de 2012
Editada: Matt J el 3 de Oct. de 2012
Gosh, I hadn't noticed that REGIONPROPS(...,'Orientation') doesn't incorporate the intensity image distribution into its calculations. That seems pretty bizarre, no? Why do so for 'WeightedCentroid', which you would obviously use to get translational position, but not offer proper intensity moment calculations to get orientation?

Iniciar sesión para comentar.

Categorías

Más información sobre Image Processing Toolbox en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by