Ralston's method function
24 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
I am trying to write a function for Ralston's method, a second order Runge Kutta method. My function does not appear to be graphing correctly in another script. Is there something wrong with my function?
function [t, y] = ralston( f, tspan, y0, n)
% ralston implement ralston method
a = tspan(1);
b = tspan(2);
h = (b - a)/n;
t = a + h*(0:n)';
y = 0*t; %vector w all elements zero
y(1) = y0;
for i = 1:n
k1 = h*f(t(i), y(i));
k2 = h*f(t(i) + 3*h/4, y(i) + 3*k1/4);
y(i+1) = y(i) + k1/3 + 2*k2/3;
end
end
Respuestas (1)
Jim Riggs
el 7 de Dic. de 2019
There is an error in your function in the k2 term. For Ralstons method, it should be:
k1 = h*f(t(i), y(i));
k2 = h*( f( t(i) + 2*h/3, y(i) + 2*k1/3 ) );
1 comentario
Jim Riggs
el 7 de Dic. de 2019
Editada: Jim Riggs
el 7 de Dic. de 2019
After some further review, there is also an error in y(i+1). Ralston's method should be:
k1 = h*f( t(i), y(i) );
k2 = h*f( t(i) + 2*h/3, y(i) + 2*k1/3 );
y(i+1) = y(i) + k1/4 + 3*k2/4;
or
k1 = f( t(i), y(i) );
k2 = f( t(i) + 2*h/3, y(i) + 2*h*k1/3 );
y(i+1) = y(i) + h*(k1/4 + 3*k2/4);
Also note that in order for the function to graph as expected, you must supply the correct starting value, y0.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!