I have an array
vk = [0 0.025 0.05 0.075 0.1 0.125 0.15 0.175].
I am writing this line
op= vk(vk>= 0.05 & vk<= 0.175)
The result which I am getting is
op =
0.0750 0.1000 0.1250 0.1500 0.1750
which is wrong, I should get
0.05 0.0750 0.1000 0.1250 0.1500 0.1750
does anyone know what I am doing wrong?
Also how I can get the indices number of the array vk and of op?

6 comentarios

Meg Noah
Meg Noah el 10 de En. de 2020
It worked for me:
vk = [0 0.025 0.05 0.075 0.1 0.125 0.15 0.175];
op = vk(vk>= 0.05 & vk<= 0.175)
>> vk = [0 0.025 0.05 0.075 0.1 0.125 0.15 0.175];
op= vk(vk>= 0.05 & vk<= 0.175)
op =
Columns 1 through 4
0.05 0.075 0.1 0.125
Columns 5 through 6
0.15 0.175
Chris Dan
Chris Dan el 11 de En. de 2020
no, its not working on this
pic2.JPG
pic3.JPG
Can you tell why?
Stephen23
Stephen23 el 11 de En. de 2020
Editada: Stephen23 el 11 de En. de 2020
"no, its not working on this ... Can you tell why?"
Can you explain why you think that it is not working?
Chris Dan
Chris Dan el 11 de En. de 2020
the value 0.05 is not included in "op", it should be included as well, what change can be done?
Chris Dan
Chris Dan el 11 de En. de 2020
Editada: Chris Dan el 11 de En. de 2020
I kind of got it,
op = vk(vk>= 0.05-0.00000000001 & vk<= 0.175)
subtracting a very small number, it is getting me the correct answer in my case...

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Meg Noah
Meg Noah el 10 de En. de 2020

0 votos

To get the indices to the vk array
vk = [0 0.025 0.05 0.075 0.1 0.125 0.15 0.175];
[idx] = find(vk>= 0.05 & vk<= 0.175);
op = vk(idx)

4 comentarios

Stephen23
Stephen23 el 11 de En. de 2020
find is not required, logical indexing is simpler and more efficient:
idx = vk>=0.05 & vk<=0.175;
op = vk(idx)
Chris Dan
Chris Dan el 11 de En. de 2020
Editada: Chris Dan el 11 de En. de 2020
@Meg Noah It is not giving the index of the first value
Meg Noah
Meg Noah el 11 de En. de 2020
Editada: Meg Noah el 11 de En. de 2020
The OP specifically asks: Also how I can get the indices number of the array vk and of op? And that is why I have a 'find' command.
When I run this code to find the indices of the vk meeting that condition, this is what is displayed:
>> idx = find(vk>=0.05 & vk<=0.175)
idx =
3 4 5 6 7 8
Remember: matlab arrays begin indexing at position 1. There is no 0th element.
>> vk(0)
Array indices must be positive integers or logical values.
The value of element 1 is 0. Since it does not meet the condition, the index 1 is not returned on the list of indices that meet the condition.
The value of element 2 is 0.025. Since it does not meet the condition, the index 2 is not returned on the list of indices that meet the condition.
The value of element 3 is 0.025. It is the first value that meets the condition, and index 3 is the first value returned on the list of indices that meet that condition.
If your problem is floating point, then maybe try recasting it. Is it being set to a double precision array initially?
vk = double(vk);
Chris Dan
Chris Dan el 12 de En. de 2020
I kind of made this loop to get the indexes of vk
vk = [0 0.025 0.05 0.075 0.1 0.125 0.15 0.175];
ind= size(vk,2);
for i = 1:1:ind
index(i) = i
end
Because first element is zero so I wasnt getting the index of that one

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el 12 de En. de 2020

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