How to write a quadratic equation solver using vectors

function [quadRoots,disc] = Q1_19041694(coeff)
coeff = (a b c);
disc = sqrt((b^2) - (4*a*c));
x1 = (disc - b)./(2*a);
x2 = (-b-disc)./(2*a);
if disc > 0
    quadRoots = [x1,x2];
elseif  disc == 0
     quadRoots = x1;
else
    quadRoots = (NaN)^4;
end

[Abdulbasit Yekeen]

Having errors in the code

[Rocky Sharaf]

class Solution {

public:

vector

<int> quadraticRoots(int a, int b, int c) {

vector

<int> roots;

int root1 = 0, root2 = 0;

// value of b^2-4ac

int temp = (pow(b, 2) - 4 * a * c);

// if b^2-4ac is less then zero then roots are imaginary

if (temp < 0)

roots

.push_back(-1);

else {

// calculate root1 and root2 using fomula

// floor function returns greatest integer below ( -b + sqrt(temp) )

// sqrt function returns square root of temp

root1

= floor((-b + sqrt(temp)) / (2 * a));

root2

= floor((-b - sqrt(temp)) / (2 * a));

// store both roots calculated in vector

// max function returns greater value between root1 and root2

// min function returns smaller value between root1 and root2

roots

.push_back(max(root1, root2));

roots

.push_back(min(root1, root2));

}

return roots;

}

};

Answer 1

[Sindar]

Search the help for one of the other students asking how to solve this exact same problem