How to use a for loop to iterate through all columns in a row, and then go down each row and iterate through all the corresponding columns in the same way?

Hi, so I have a vector called Currents (size is 531 by 758), and a vector called r (size is 531 by 1). My equation is V=Currents/r. Using this equation, I need to create a new vector V, which has the same size as Currents. How can I use a for loop to go through all 758 columns corresponding to each row, and calculate V for each of those columns using the corresponding r value for that row, and then repeat this same step for each row 531 times until the end? Any help would really be appreciated!!!

EDIT: Here is the code I was writing. It isn't giving me the correct output though.

V=zeros(size(Currents))

for i=1:length(r)

for j=1:length(Currents)

V(i,j)=Currents(i,j)/r(i)

end

end

Answer 1

[KSSV]

V = Currents./r ; 

Where Currents is your 531*758 matrix and r is 531*1 matrix.

[Zuha Yousuf]

Hi! That gives me this error:

Incorrect dimensions for matrix multiplication. Check that the number of columns in the first

matrix matches the number of rows in the second matrix. To perform elementwise multiplication, use

'.*'.

I'm pretty sure it has to be done using a for loop. Because the value we're using for r changes for each row.

[KSSV]

What are the sizes of your Currents and r?

[Zuha Yousuf]

Currents is a matrix with size 531 by 758, and r has a size of 531 by 1.

[KSSV]

Why did you use *?

Currents = rand(531,758) ; 
r = rand(531,1) ; 
v = currents./r ; 

[Zuha Yousuf]

I didn't use that. What I'm saying is, there is a different r value to be used for the calculation for each row. So we do need to use a for loop. I already have the values for Currents and r, so why are we initializing them using rand?

Answer 2

[darova]

Use repmat

a = rand(531, 758);
r = rand(531, 1);
R = repmat(r,[1 758])
res = a./R;