Calculating grades in a while loop

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Angel Sanchez
Angel Sanchez el 13 de Feb. de 2020
Comentada: Angel Sanchez el 13 de Feb. de 2020
If I have a array of students grade scores, score=[82, 75, 78, 82, 90, 87], and i want to calculate the number of A's, B's. How would i do that for example to be a grade of A it must be greater or equal to 90, which on the score is shows 2. How can i output that which it will give me the value of 2, as well as for b which would give me 3 which is greater or equlat to 80.

Respuestas (2)

Bhaskar R
Bhaskar R el 13 de Feb. de 2020

Jakob B. Nielsen
Jakob B. Nielsen el 13 de Feb. de 2020
You don't need a while loop for that - it is easy with logic indexing, like so:
score=[82 75 78 82 90 87];
A=score(score>=90); %take the indexes of score, for which that same index of score is greater than or equal to 90.
numA=numel(A);
B=score(score>=80 & score<90);
numB=numel(B);
  3 comentarios
Jakob B. Nielsen
Jakob B. Nielsen el 13 de Feb. de 2020
Weird homework to ask you to do more than you need. You should be cheeky, and hand in the above solution as well as the loop :D
Must it be a while loop, specifically, or can it be a for loop?
Angel Sanchez
Angel Sanchez el 13 de Feb. de 2020
yes a while loop

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