Definite integral without symbolic variables

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Pilar Jiménez
Pilar Jiménez el 18 de Feb. de 2020
Respondida: Star Strider el 18 de Feb. de 2020
Hi good day.
I want to request your support to know if it is possible to perform a definite integral without the use of matlab integration commands since it asks for symbolic variables to be established and I need to work with variables that are defined. I need to perform this integration as part of a larger algorithm and that is why I need them not to be symbolic variables.
An example of the function that I must integrate is the following:
k = 2*pi;
L1=0.5;
L2=0.5;
d=0.2;
R1 = sqrt(d^2 + 0.5^2);
R2 = sqrt(d^2 + 0.6^2);
R0 = sqrt(d^2 + 0.7^2);
G1 = exp(-j*k*R1)./R1;
G2 = exp(-j*k*R2)./R2;
G0 = exp(-j*k*R0)./R0;
fun = (G1 + G2 - 2*cos(k*L1/2) * G0) .* sin(k*(L2/2-abs(z)));
The integral is defined with respect to z from -L1 / 2 to L1 / 2. I hope you can help me.
Thanks in advance.

Respuestas (1)

Star Strider
Star Strider el 18 de Feb. de 2020
Create ‘fun’ as an anonymous function, then use the integral function:
fun = @(z) (G1 + G2 - 2*cos(k*L1/2) * G0) .* sin(k*(L2/2-abs(z)));
Iz = integral(fun, -L1/2, L1/2)
producing:
Iz =
-0.912687739195403 + 0.513810248651795i

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