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I have a matrix that contains strings and i have to find words in it.

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I have to create a program that gives you the position of the first letter of the word you input and if it's from left to right or right to left.
for example if you input the word 'er' it should tell you that:
The word was found from left to right at the position (1,1)
Please help
['e' 'r' 'd' 'u' 'o' 'p' 'i' 'e' 'c' 'e';...
't' 'p' 'r' 'o' 'm' 'e' 't' 'a' 'l' 'l';...
'i' 's' 'd' 'p' 's' 't' 'u' 'b' 'a' 'a';...
'g' 'e' 'p' 'o' 'm' 's' 'i' 'c' 'm' 'v';...
's' 't' 'e' 'i' 'u' 'r' 'a' 't' 'e' 'a';...
'o' 't' 'n' 'n' 'c' 'b' 'c' 'b' 'r' 'g';...
'u' 'e' 'f' 'c' 't' 'e' 'l' 'u' 'l' 'e';...
'v' 'l' 'i' 'o' 'r' 'b' 'r' 'o' 'i' 'e';...
'e' 'l' 'e' 'n' 'u' 'u' 'i' 'r' 'n' 't';...
'r' 'i' 'v' 'i' 'e' 'r' 'e' 'j' 'g' 'a';...
'a' 'a' 'r' 'n' 'e' 'l' 'r' 'r' 'o' 'c';...
'i' 'p' 'e' 'c' 'a' 'r' 'a' 't' 't' 'u';...
'n' 't' 'e' 'g' 'a' 'i' 'l' 'l' 'a' 'd';...
'f' 'i' 'l' 'o' 'n' 'o' 'l' 'a' 't' 'e']

  2 Comments

Stephen Cobeldick
Stephen Cobeldick on 3 Mar 2020
The character array shown in the question can be written more simply as:
['erduopiece';...
'tprometall';...
'isdpstubaa';...
'gepomsicmv';...
'steiuratea';...
'otnncbcbrg';...
'uefctelule';...
'vliorbroie';...
'elenuuirnt';...
'rivierejga';...
'aarnelrroc';...
'ipecarattu';...
'ntegaillad';...
'filonolate']
or:
['erduopiece';'tprometall';'isdpstubaa';'gepomsicmv';'steiuratea';'otnncbcbrg';'uefctelule';'vliorbroie';'elenuuirnt';'rivierejga';'aarnelrroc';'ipecarattu';'ntegaillad';'filonolate']

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Accepted Answer

Jalaj Gambhir
Jalaj Gambhir on 3 Mar 2020
Hi,
You can use strfind function to determine the presence of elements in you char array.
matrix = ['a','b','d','f';
'c','t','a','g';
'f','a','n','p';
'd','b','a','b'];
word = 'ab';
for i=1:length(matrix)
str = matrix(i,:);
idxL2R = strfind(str,word);
idxR2L = strfind(str,flip(word));
result = ['for string = ',str,' indexL2R while searching for word = ',word,
' is = ',int2str(idxL2R), ' indexR2L is = ', int2str(idxR2L)];
disp(result);
end

  2 Comments

Jalaj Gambhir
Jalaj Gambhir on 3 Mar 2020
Result:
for string = abdf indexL2R while searching for word = ab is = 1 indexR2L is =
for string = ctag indexL2R while searching for word = ab is = indexR2L is =
for string = fanp indexL2R while searching for word = ab is = indexR2L is =
for string = dbab indexL2R while searching for word = ab is = 3 indexR2L is = 2

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More Answers (1)

Stephen Cobeldick
Stephen Cobeldick on 3 Mar 2020
>> mat = ['erduopiece';'tprometall';'isdpstubaa';'gepomsicmv';'steiuratea';'otnncbcbrg';'uefctelule';'vliorbroie';'elenuuirnt';'rivierejga';'aarnelrroc';'ipecarattu';'ntegaillad';'filonolate'];
>> baz = @(r,c)[r*ones(numel(c),1),c(:)];
>> vec = num2cell(1:size(mat,1));
>> fun = @(s)cell2mat(cellfun(baz,vec(:),strfind(num2cell(mat,2),s),'uni',0)).';
>> str = 'er';
>> fprintf('The word was found from left to right at the position (%u,%u)\n',fun(str))
The word was found from left to right at the position (1,1)
The word was found from left to right at the position (10,5)
>> fprintf('The word was found from right to left at the position (%u,%u)\n',fun(fliplr(str)))
The word was found from right to left at the position (10,6)

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