How to replace a column in a text file with time and plot a graph from it?

The first column shows the frequency of data aquisition, which is 1000 hz. But I need to replace the first column of the text file with time, starting with 0 secs, then 0.0001s till 60s. it is then used to plot a graph of data points, where the 2nd and 3rd columns are outputs. The picture of text file is attached.

Any help is appreciated.

I tried with the following command but it didnt work and took forever.

data = load('test1.txt');

data(:, 1) = 0:0.0001:60000;

Answer 1

[KALYAN ACHARJYA]

Please note: It should be column vector

data = load('test1.txt');
data(:, 1) =[0:0.0001:60000]';

[Savouri]

Thanks for the answer. But it didnt work, the error message below is displayed, how do I fix it?

Unable to perform assignment because the size of the left side is 62000-by-1 and the size of the right side is 600000001-by-1.

Error in Untitled2 (line 2)

data(:, 1)=[0:0.0001:60000]';

[KALYAN ACHARJYA]

Please attach the text file.

[Savouri]

here is the zip file that contains the text file. Thanks!

[KALYAN ACHARJYA]

Its simple

>> length(data(:,1))
ans =
       62000
>> length(0:0.0001:60000)
ans =
   600000001

Make the array 0:0.0001:60000 having the same length as length(data(:,1)), which is 62000, or use

   linspace(0,60000,62000); % set the step size as requred 

[KALYAN ACHARJYA]

Savvas Dong Comment moved here