string to argument in legend
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Ivan Perez Avellaneda
el 3 de Abr. de 2020
Comentada: Ivan Perez Avellaneda
el 3 de Abr. de 2020
I am trying to generate the legend for N plots. Each plot uses latex code. For example, in the following picture there are 10 sets and I inserted legends for 4 sets. I did
it manually using
legend(strcat('$${\mathcal X}_',num2str(3), '$$'), strcat('$${\mathcal X}_',num2str(2), '$$'), strcat('$${\mathcal X}_',num2str(1), '$$'),strcat('$${\mathcal X}_',num2str(0), '$$'),'Interpreter','latex')
So I wanted to generate the argument of the legend as a string. I did
for i=0:Nint-1
legI = strcat("strcat('$${\mathcal X}_',num2str(",num2str(Nint-i),"), '$$')");
legII=strcat(legII,legI,',');
end
legII=strcat(legII,strcat("strcat('$${\mathcal X}_',num2str(",num2str(0),"), '$$')"));
where Nint=10 (the number of sets). This gives me
legII =
"strcat('$${\mathcal X}_',num2str(10), '$$'),strcat('$${\mathcal X}_',num2str(9), '$$'),strcat('$${\mathcal X}_',num2str(8), '$$'),strcat('$${\mathcal X}_',num2str(7), '$$'),strcat('$${\mathcal X}_',num2str(6), '$$'),strcat('$${\mathcal X}_',num2str(5), '$$'),strcat('$${\mathcal X}_',num2str(4), '$$'),strcat('$${\mathcal X}_',num2str(3), '$$'),strcat('$${\mathcal X}_',num2str(2), '$$'),strcat('$${\mathcal X}_',num2str(1), '$$'),strcat('$${\mathcal X}_',num2str(0), '$$')"
then I did
legend(convertStringsToChars(legII),'Interpreter','latex');
but it didn't interepret the latex nor give me the Nint=10 legends.
2 comentarios
the cyclist
el 3 de Abr. de 2020
Here is why what you are doing doesn't work. Take the simplified case of only trying to make the legend with X0. The "manual" version is this code:
legend(strcat('$${\mathcal X}_',num2str(0), '$$'),'Interpreter','latex')
But your "automated" version evaluates to this:
legend('strcat('$${\mathcal X}_',num2str(0), '$$')','Interpreter','latex')
Respuestas (1)
Walter Roberson
el 3 de Abr. de 2020
for i=0:Nint
legI(i+1) = "$${\mathcal X}_" + Nint-i + "$$";
end
legend(legI)
1 comentario
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