Generalized Forced Van Der Pol Oscillator Phase Plot

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Thomas Ward
Thomas Ward el 16 de Abr. de 2020
Comentada: george korris el 15 de Abr. de 2021
Hello,
I am trying to write a program to solve a forced van der pol oscillator and give its phase plot. I found a code on these forums, posted by @KSSV that solved an unforced van der pol oscillator and I just added a forcing term, and it worked. Here is the code
function VanderPol()
[t,y] = ode23(@vdp1,[0 20],[2; 0]);
plot(t,y(:,1),'-o',t,y(:,2),'-o')
title('Solution of van der Pol Equation (\mu = 1) with ODE23');
xlabel('Time t');
ylabel('Solution y');
legend('y_1','y_2')
figure
plot(y(:,1),y(:,2))
title('Phase plane plot')
end
function dydt = vdp1(t,y)
dydt = [y(2); 3*(1-y(1)^2)*y(2)-y(1)+8*sin(4*t)];
end
I was able to go in and play with the variables to obtain different results, which was great, but ideally I would want to generalize the code such that the second line read
[t,y] = ode23(@vdp1,[0 20],[idis; ivel]);
And the line prior to end read
dydt=[y(2); mu*(1-y(1)^2)*y(2)-y(1)+A*sin(omega*t)];
And then be able to call VanderPol(idis, idel, mu, A, omega) and be able to solve that without having to go in and manually change it each time

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Star Strider
Star Strider el 17 de Abr. de 2020
Try this:
function [t,y] = VanderPol(idis, ivel, mu, A, omega)
[t,y] = ode23(@vdp1,[0 20],[2; 0]);
plot(t,y(:,1),'-o',t,y(:,2),'-o')
title('Solution of van der Pol Equation (\mu = 1) with ODE23');
xlabel('Time t');
ylabel('Solution y');
legend('y_1','y_2')
figure
plot(y(:,1),y(:,2))
title('Phase plane plot')
function dydt = vdp1(t,y)
dydt = [y(2); mu*(1-y(1)^2)*y(2)-y(1)+A*sin(omega*t)];
end
end
Then to call it:
idis = 2;
ivel = 0;
A = 8;
omega = 4;
mu = 3;
[t,y] = VanderPol(idis, ivel, mu, A, omega);
figure
plot(t,y)
grid
I added a tweak so that you can get the integrated results from your funciton. It is otherwise what you wrote.
.
  3 comentarios
Star Strider
Star Strider el 17 de Abr. de 2020
As always, my pleasure!
george korris
george korris el 15 de Abr. de 2021
hey guys is this code solving this equation: and what does: Solution of van der Pol Equation (\mu = 1) with ODE23' that the first figure has as title mean?

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