separating element in cell according to some condition

I have A

A={[237;238;241;243], [238;237;241;243;247], [241;237;238;243;247],...
    [243;237;238;241;247;310],[247;238;241;243;310;381],[310;243;247],[381;247;310] }

I want to use this algorithm

First cell

1. A{1}=[237;238;241;243]
2. Put first and second element of A{1} in temp (temp=[237,238])
3. Choose last element in temp, if it has only 2 element (238)
4. Choose cell in A that the first element is 238 (A{2}=[238;237;241;243;247])
5. Third element in A{1} is 241
6. Does 241 belong to A{2}? yes
7. So, we could add 241 to temp (temp=[237,238, 241])
8. 4th element in A{1} is 243
9. Does 243 belong to A{2} and A{3}? Yes ---> I have a problem to write a code for this part
10. So, we could put 243 on temp (temp=[237,238, 241,243])

Result in this cell, temp =[237,238, 241,243]) 

Answer 1

[Mehmed Saad]

I will give you a hint for A{1}(4) with A{2} and A{3}

1. compare 4th element of A{1} with A{2} all element
2. if any of them is 1 it means it is inside that cell. it will give you output in the form of logical array [0 0 1 0]
3. compare 4th element of A{1} with A{3} all element, and sum the logical array, if its sum is greater than 0 it means that 4th element of A{1} exist in A{3}. apply and operation on the logical array given by step 2 with current output
4. feed these logical index to A{2}(logical index)

temp = [temp;A{2}(and((sum(A{3}==A{1}(4))>0),(A{2}==A{1}(4))))];