replace numbers of margins of metrix( how t0 fix it ?)
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i want to replace margins of matrix by another number by using 'for loop'
{im=[0 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1;
0 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1;
0 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1;
0 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1;
0 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1;
0 1 0 0 0 0 0 0 0 0 0 1 1 1 1 1];
[r c]= size(im);
for i=1:size(im(1,end,:))
for j=1:size(im,2)
im(i, j)=3;
end
end
}
it only return first row by replacing with '3'.it should at least return first and last row with '3'.... but it doesn't. how do i write a code to replace all margins(first_row, first_column, last_row and last_column) by '3' using 'for loop'....
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Respuesta aceptada
Walter Roberson
el 10 de Abr. de 2011
im is a 2 dimensional array, so in your expression im(1,end,:) the : is going to just reference the entire 2D array, leaving the expression equivalent to im(1,end) . im(1,end) refers, though, to im(1,size(im,2)) which is the single element that is the top right corner of the array. You then take size(im(1,end,:)) so that size() is going to be referring to size() of something that is 1x1 and so "i" is going to refer only to the first row.
2 comentarios
Walter Roberson
el 10 de Abr. de 2011
Sure it is possible to use for loops for what you are doing: what I pointed out is the part your code fails at. Think more closely about what it is you want to take the size() of.
Más respuestas (2)
Andrei Bobrov
el 10 de Abr. de 2011
[m,n]=size(im);for ii = 1:m,for jj = 1:n,if ii == 1 | ii == m | jj == 1 | jj == n, im(ii,jj) = 3; end;end;end
Andrei Bobrov
el 10 de Abr. de 2011
im([true(1,n);repmat([true false(1,n-2) true],m-2,1);true(1,n)])=3
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