Error using matlab.ui.control.EditField/set.Value 'Value' must be a character vector or a string scalar.
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Max-Henri Froger
el 24 de Abr. de 2020
Comentada: Steven Lord
el 20 de Jun. de 2023
Hi,
I got a question about app deisgner. I am using 2 edit fields (text). The first one is to write a value (e.g : 2). For the second I would like matlab to calculate directly (without action) the multiplication of the first edit field by 3,6. I am using edit field (text) instead of edit field (num) because edit field (text) allow the "Value changing function".
In the last line of the code below, matlab says " Error using matlab.ui.control.EditField/set.Value 'Value' must be a character vector or a string scalar." The first edit field is called "SCx" and the second is "A2".
function SCxEditFieldValueChanging(app, event)
value = event.Value;
value2 = value+3;
app.A2EditField.Value = value2;
end
Need help to understand my mistake or to help me find a solution.
Thanks,
Max-Henri Froger
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Respuesta aceptada
Tommy
el 24 de Abr. de 2020
value as obtained from event.Value is a character vector, so adding 3 to it does not do what you may think it does:
>> '4'+3
ans =
55
Then, value2 is a double, so you cannot use it to set app.A2EditField.Value, which must be a character vector or string scalar as the error message indicates. Try this:
value2 = num2str(str2double(value)+3);
3 comentarios
Shelynna Adjana Banawe
el 20 de Jun. de 2023
i've similar issue but i used number field instead of text
a = app.val1.Value;
b = app.val2.Value;
app.results.Value = a+b;
this is the error i got
Error using matlab.ui.control.EditField/set.Value
'Value' must be a character vector or a string scalar.
Steven Lord
el 20 de Jun. de 2023
It seems from the error message that your app.results field is an uieditfield with style equal to "text" whereas your app.val1 and app.val2 are uieditfields with style equal to "numeric". Either make your app.results have style "numeric" or convert the numeric result of a+b into a string before trying to assign it to the Value property of app.results.
n = 42 % numeric result
s = string(n) % string result
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