The following Matlab code runs only half of the for loop. Can anyone help me figure out the problem?
4 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
jarul
el 28 de Abr. de 2020
Comentada: jarul
el 29 de Abr. de 2020
Here is the part of the matlab Code that I was working for an SDR development.
In the following code, when the ind in the for loop below exceeds four or more than
half fo the loop, it stops and gives me an error.
Can someone help me and let me know the reason why it happens in MATLAB.
// The code begins here.
NumFrames =10;
%% Build OFDM Modulator
FFTLength = 64;
NumGuardBandCarriers = [6; 5];
NumDataCarriers = 48;
CyclicPrefixLength = 16;
PilotCarrierIndices = [12;26;40;54];
NumOFDMSymInPreamble = 5;
NumBitsPerCharacter = 7;
SampleRate = 20e6;
Fs = SampleRate;
msgInBits = repmat(randi([0 1], NumDataCarriers, 1),10160, 1);
PayloadBits = msgInBits(:);
MSDU = ceil(length(PayloadBits)/(NumFrames*NumDataCarriers));
txData = zeros(0,1);
for ind = 0 : (NumFrames-1)
framebody = PayloadBits((ind*MSDU*NumDataCarriers)+1:(NumDataCarriers*MSDU)*(ind+1),:);
txData = [txData; framebody];
PayloadBits((ind*MSDU*NumDataCarriers)+1:(NumDataCarriers*MSDU)*(ind+1),:)=[];
if(ind == 4) // When Ind exceeds more than half the loop, it creates error message.
return
end
end
1 comentario
Steven Lord
el 28 de Abr. de 2020
What is the full and exact text of the error message you receive? Show all the text displayed in red and/or orange when you receive the error.
Respuesta aceptada
Tommy
el 28 de Abr. de 2020
PayloadBits((ind*MSDU*NumDataCarriers)+1:(NumDataCarriers*MSDU)*(ind+1),:)=[];
This line changes the size of PayloadBits, but you have set up MSDU, NumDataCarriers, and ind based on the initial size of PayloadBits. Will it work if you omit this line? i.e.
for ind = 0 : (NumFrames-1)
framebody = PayloadBits((ind*MSDU*NumDataCarriers)+1:(NumDataCarriers*MSDU)*(ind+1),:);
txData = [txData; framebody];
end
Más respuestas (0)
Ver también
Categorías
Más información sobre Signal Processing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!