Simple Iterative expression needed solved

1 visualización (últimos 30 días)
James Paltani
James Paltani el 30 de Abr. de 2020
Comentada: Walter Roberson el 30 de Abr. de 2020
Assuming w is an integer (w = 1, 2, 3, …), write an iterative calculation to determine the minimum w value that will bring the result of the following expression to greater than 10,000. Display this minimum w value and the corresponding result of the expression.

Respuestas (2)

Walter Roberson
Walter Roberson el 30 de Abr. de 2020
initialize. while the condition is not met, increment.
  4 comentarios
James Paltani
James Paltani el 30 de Abr. de 2020
Editada: James Paltani el 30 de Abr. de 2020
This is what i have so far.. it says illegal "greater than" operator. What should i differently
clc,clear
syms w
e = sqrt((10*w^2)-4*w+2);
for e > 10000,
solve(w)
Walter Roberson
Walter Roberson el 30 de Abr. de 2020
syms w
e = sqrt((10*w^2)-4*w+2);
w = ceil(max(double(solve(e==10000))));
But this does not use a loop like you are required to do. You should not be using symbolic toolbox for this problem.
You should be initializing w to the lowest value of the range. Then you calculate e based on that w. Test whether it has reached the necessary value yet. If it has not, increment w and recalculate e and loop back.

Iniciar sesión para comentar.


Mrutyunjaya Hiremath
Mrutyunjaya Hiremath el 30 de Abr. de 2020
w = 1; y = 0;
while(y < 10000)
% your equation
y = sqrt(10*w*w - 4*w + 2);
w = w + 1;
end
disp(w)
disp(y)
  1 comentario
Walter Roberson
Walter Roberson el 30 de Abr. de 2020
We recommend against providing complete solutions to homework assignments.

Iniciar sesión para comentar.

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by