building a 3D matrix
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    Qian
 el 30 de Oct. de 2012
  
    
    
    
    
    Comentada: Gowthami Odeti
 el 9 de Nov. de 2017
            I understand how the following works, x=[a b; c d]; x(:,:,2)=x; which will give x as 3-D matrix. However, i'm writing a code for which i need x to be updated each time. for example, for i=1:2; for j=1:3; x(:,j)=[i+j+1;j*2 ]; end x(:,:,i)=x end
In this case, I want to have a result of 2*3*2 matrix, x(:,:,1) =
     3     4     5
     2     4     6
x(:,:,2) =
     4     5     6
     2     4     6
However, it turns out I only get
x(:,:,1) =
     4     5     6
     2     4     6
x(:,:,2) =
     4     5     6
     2     4     6
I know the problem is the x(:,:,i)=x line as x gets updated and renewed for each loop and covered by the new data again.
But I couldn't assign new name for building this matrix.
Can anyone help
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