- MATLAB's function input and output arguments are entirely positional. Their names are irrelevant.
- When calling a function, you need to provide the inputs that are used in the code that actually runs, e.g. if only the 3rd input is used in the code that runs then the 3rd input must be provided.
- ...but because of rule 1., this means you also also need to provide the 1st and 2nd inpust as well, although their values will be completely ignored because the code that runs does not use them.
- Unused inputs cannot be left "blank". Usually an empty array is used.
how does a function invoke the inputs?
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Shuangfeng Jiang on 6 May 2020
Commented: Shuangfeng Jiang on 7 May 2020
function [result] = test02(type,a,b,c,d)
%This function is used to test what will happen if only part of the inputs
%are needed to get the result.
warning('Unexpected input type. Please check the input.')
I wonder how Matlab function tacitly 'uses' the inputs, so I wrote the function above and type the piece of codes below in the command line to see what if only part of the inputs are given. Unexpectedly, no error came up (Personally 'c' and 'd' are not essential to get the result for case '1'). Could anyone explain the reason why the function still works when only part of the inputs (type, a, b) are given? What's the mechanism of calling the inputs in a Matlab function?
a=1; b=2; c=3; d=4;
[result] = test02(type,a,b)
Stephen23 on 6 May 2020
Edited: Stephen23 on 6 May 2020
More Answers (1)
KSSV on 6 May 2020
It is because, your type = '1' needs only two inputs a,b ..
You try using type = '2' with only two inputs..it will throw error. For the type = '1' case, it needs only two inputs a, b nd you have provided them so there is no error.
Rik on 6 May 2020
You can put in anything you want, because your function is going to ignore the actual contents of the variable. Usually people use an empty array  to show that an input is ignored.
result = test02(type,a,,c)
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