Indexing structure without using scalars

Consider following structure:

mm(1,1).no=1;
mm(2,1).no=2;
mm(3,1).no=3;
mm(3,1).mtx=[3;3;3];
mm(2,1).mtx=[2;2;2];
mm(1,1).mtx=[1;1;1];
a1 = cat(1, mm([1,2]).no)

a1 =

       1
       2

a2 = cat(1, mm([1,2]).mtx(1))
Scalar index required for this type of multi-level indexing.

Is there a work-around for this type of indexing?

[Matt J]

If your mtx and no data re all the same size, as in this example, it makes more sense to hold them in a scalar struct

 mm.no=[1;2;3];
 mm.mtx=[1 2 3; 1 2 3; 1 2 3];

Then you can easily extract pieces that you need

 a1=mm.no(1:2);
 a2=mm.mtx(:,1);

[Milos]

This was just an example structure. Data is different, and matrices are way larger.

Answer 1

[Sean Little]

Unfortunately, Matlab does not support multi-level indexing like other languages do. You are probably going to have to create an intermediate variable.

a1 = [mm(1:2).mtx];
a2 = a1(1,:)

[Milos]

Thanks, that's what I feared.

Answer 2

[Matt J]

 tmp=cat(1,mm([1,2]).mtx); 
 a2=tmp(1)