How to fix a matrix?Dimensions of arrays being concatenated are not consistent

I have a problem with the matrix dimension in my code:

I just want to calculate the average at the end of the code. This code actually works with the all the matrices(a big table of double) I have used before. However now I am struggling with this one table called UgisM0L06, that I will also upload. I dont understand how can I fix the fact that the matrix "L_PeaksM0L06 ", resulting from the last FOR LOOP ,does not give the same number of elements for each column.

I will upload also the table of doubles UgisM0L06.

Please, any help would be appreciated. let me know if something is not cler.

CODE:

% Shoes UgisM0L06

L_3=UgisM0L06(:,1:99);

% D_18(1:15,32)=[0];

mask = sum(L_3, 2)~=0;

comps = bwconncomp(mask);

compMaskList = comps.PixelIdxList; %chunks positions(steps rows)

L_3_components = cell(numel(compMaskList), 1);

for i=1:numel(compMaskList)

step{i} = L_3(compMaskList{i}, :);

if size(step{i})<=[30 99]

step{i}=[];

end

end

n_steps=step(~cellfun('isempty',step));

% n_steps=[step(1:2),step(8:10),step(13:19)];

if length(n_steps)>=12

steps=n_steps(1:12);

size(steps)

end

for i=1:length(n_steps)

Big_ToeM0L06{i}=[n_steps{i}(:,[83:84]),n_steps{i}(:,[90:91]),n_steps{i}(:,96)];

Peak_HalluxM0L06(i) = max(Big_ToeM0L06{i}, [], 'all');

Other_ToesM0L06{i}=[n_steps{i}(:,[81:82]),n_steps{i}(:,[85:89]),n_steps{i}(:,[92:95]),n_steps{i}(:,[97:99])];

Peak_PhalangesM0L06(i)=max(Other_ToesM0L06{i}, [], 'all');

MedFM0L06{i}=[n_steps{i}(:,[62:63]),n_steps{i}(:,[69:70]),n_steps{i}(:,[76:77])];

Peak_Mtpj1M0L06(i)=max(MedFM0L06{i}, [], 'all');

C_FM0L06{i}=[n_steps{i}(:,[64:66]),n_steps{i}(:,[71:73]),n_steps{i}(:,[78:80])];

Peak_Mtpj23M0L06(i)=max(C_FM0L06{i}, [], 'all');

LatFM0L06{i}=[n_steps{i}(:,[60:61]),n_steps{i}(:,[67:68]),n_steps{i}(:,[74:75])];

Peak_Mtpj45M0L06(i)=max(LatFM0L06{i}, [], 'all')

end

L_PeaksM0L06=[Peak_HalluxM0L06',Peak_PhalangesM0L06',Peak_Mtpj1M0L06',Peak_Mtpj23M0L06',Peak_Mtpj45M0L06'];

for j=1:5

AverageM0L06(j) =mean(L_PeaksM0L06(:,j));

end

AveragesM0L06=[AverageM0L06]

Answer 1

[Image Analyst]

I didn't run your code but usually "Dimensions of arrays being concatenated are not consistent" means that you are stitching/concatenating things of different sizes. For example, you are

1. Vertically concatenating matrices with different numbers of rows, or
2. Horizontally concatenating matrices with different numbers of columns.

Example for case 1

1 2

3 4

cannot be concatenated with

1 2 3

3 4 5

because column 3 cannot be blank in rows 1 and 2.

Which is your situation?

Actually, I almost just repeated the FAQ: https://matlab.fandom.com/wiki/FAQ#.E2.80.9CDimensions_of_arrays_being_concatenated_are_not_consistent..E2.80.9D

[Geraldine Ejimadu]

Hi Image Analyst, thank you for replying

I believe my case is the second one (case 2)?

For example:

I would like to obtain the matrix A made of different vectors B, C , D displayed in column.

B=[1;1] C=[2;2] D=[3;3]

A would be like:

1 2 3

1 2 3

However, in my code it seems like one of the vectors(for example C) is longer, so I unfortunately get:

1 2 3

1 2 3

2

This is case 2, if I am not mistaking?

[Image Analyst]

You can do this:

B=[1;1] 
C=[2;2] 
D=[3;3]
A = [B, C, D]

B =

1

1

C =

2

2

D =

3

3

A =

1 2 3

1 2 3

[Geraldine Ejimadu]

I understand what you say. I think the last FOR LOOP in my code is already doing it, but for this particular matrix that I have to use (UgisM0L06), it is not working. I have used more that twenty large matrixes, and they work, except for this one.