Write a program that calculates sum of the integers numbers

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Aaron Moris
Aaron Moris el 11 de Abr. de 2011
Comentada: DGM el 4 de Mzo. de 2023
What is the product if the question is write a program that calculates and prints the sum of the even integers from 2 to 30?

Respuestas (5)

Florin Neacsu
Florin Neacsu el 11 de Abr. de 2011
2+4+6+...+30=2(1+2+3+...+15)=2*(15*16)/2=15*16
So 2+4+...+n = floor(n/2)*(floor(n/2)+1).
Regards, Florin

Matt Fig
Matt Fig el 11 de Abr. de 2011
The product would be the sum of the even integers from 2 to 30 ;-).
Seriously, what have you tried so far on this homework problem?
  2 comentarios
Sean de Wolski
Sean de Wolski el 11 de Abr. de 2011
You might need some bubble wrap for that.
Paulo Silva
Paulo Silva el 11 de Abr. de 2011
I hate when it takes more time to understand what people want than to make their answer!

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Paulo Silva
Paulo Silva el 11 de Abr. de 2011
v=2:30;
sum(v(~mod(v,2)))
  3 comentarios
Image Analyst
Image Analyst el 15 de Ag. de 2017
mod(v, 2) will be either 0 or 1. The tilde inverts that, so 0 becomes 1, and 1 becomes 0.
DGM
DGM el 4 de Mzo. de 2023
Importantly, using ~ implicitly casts the numeric result from mod() to logical (along with doing the inversion). Otherwise, the indexing operation would fail if the indices were numeric 0 and 1, as you'd be trying to access the zeroth element of v.

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Doug Eastman
Doug Eastman el 11 de Abr. de 2011
or
sum(2:2:30)
  2 comentarios
Paulo Silva
Paulo Silva el 11 de Abr. de 2011
that's simple but if you change the start value from 2 to 1 you do the sum of odd numbers instead, also if the last value is 31 or some odd number the result won't be correct, unfortunately that's not very flexible code.
Paulo Silva
Paulo Silva el 11 de Abr. de 2011
btw that does work and is a good answer for the question (only if the values don't change), +1 vote

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Matt Tearle
Matt Tearle el 11 de Abr. de 2011
disp(240)
Or, for pedants who claim that evaluation is not the same as calculation,
disp(239+1)
  1 comentario
Sean de Wolski
Sean de Wolski el 11 de Abr. de 2011
This is definitely the most compact and efficient way to do this. +1.

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