Write a program that calculates sum of the integers numbers
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What is the product if the question is write a program that calculates and prints the sum of the even integers from 2 to 30?
Respuestas (5)
Florin Neacsu
el 11 de Abr. de 2011
2 votos
2+4+6+...+30=2(1+2+3+...+15)=2*(15*16)/2=15*16
So 2+4+...+n = floor(n/2)*(floor(n/2)+1).
Regards, Florin
Matt Fig
el 11 de Abr. de 2011
1 voto
The product would be the sum of the even integers from 2 to 30 ;-).
Seriously, what have you tried so far on this homework problem?
2 comentarios
Sean de Wolski
el 11 de Abr. de 2011
You might need some bubble wrap for that.
Paulo Silva
el 11 de Abr. de 2011
I hate when it takes more time to understand what people want than to make their answer!
Paulo Silva
el 11 de Abr. de 2011
v=2:30;
sum(v(~mod(v,2)))
3 comentarios
Brother_Devil
el 15 de Ag. de 2017
Hi Paulo, this works fine but what is operator ~ doing here? Its hard to understand what exactly is happening after ~. I am new to coding.
Image Analyst
el 15 de Ag. de 2017
mod(v, 2) will be either 0 or 1. The tilde inverts that, so 0 becomes 1, and 1 becomes 0.
DGM
el 4 de Mzo. de 2023
Importantly, using ~ implicitly casts the numeric result from mod() to logical (along with doing the inversion). Otherwise, the indexing operation would fail if the indices were numeric 0 and 1, as you'd be trying to access the zeroth element of v.
Doug Eastman
el 11 de Abr. de 2011
or
sum(2:2:30)
2 comentarios
Paulo Silva
el 11 de Abr. de 2011
that's simple but if you change the start value from 2 to 1 you do the sum of odd numbers instead, also if the last value is 31 or some odd number the result won't be correct, unfortunately that's not very flexible code.
Paulo Silva
el 11 de Abr. de 2011
btw that does work and is a good answer for the question (only if the values don't change), +1 vote
Matt Tearle
el 11 de Abr. de 2011
disp(240)
Or, for pedants who claim that evaluation is not the same as calculation,
disp(239+1)
1 comentario
Sean de Wolski
el 11 de Abr. de 2011
This is definitely the most compact and efficient way to do this. +1.
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