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Avoiding for loop and if

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Giovanni Gardan
Giovanni Gardan el 19 de Mayo de 2020
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
I'd like to avoid the following "for loop". Is it possible?
In the following code, the matrix CAR_GEN is the input. This matrix has rows number=1000, and column number=4. In the first column of this matrix there are two possibilities: or 'G' or 'C', and if I have 'C' i have to do the operation under the if-test and finally find the vector ''Scarto''.
Is it possible to check directly if the element of the first column is 'C' and then do the operation in order to find 'Scarto', in order to save time?
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Scarto = zeros (N_nodi_tot - N_nodi_gen,1); %Array initialization
for Riga = 1:100000
if CAR_GEN(Riga,1) == abs('C')
Ncar = CAR_GEN(Riga,2);
Pcar = CAR_GEN(Riga,3)/Nbase;
Qcar = CAR_GEN(Riga,4)/Nbase;
Nload = Ntot(Riga,1);
Scarto(Ncar,1) = Nload - (Pcar + 1i*Qcar);
end
end
---------------------------------------
----------------------------------------------------------------------------------------
Thanks!
  3 comentarios
Giovanni Gardan
Giovanni Gardan el 19 de Mayo de 2020
Thank you very much for your answer. Is this the right way to use logical indexing?
Scarto = zeros (N_nodi_tot - N_nodi_gen,1);
cond = (CAR_GEN(:,1) == abs('C'));
Ncar = CAR_GEN(cond,2);
Pcar = CAR_GEN(cond,3)/Nbase;
Qcar = CAR_GEN(cond,4)/Nbase;
Nload = Ntot(cond,1);
Scarto(Ncar,1) = Nload - (Pcar + 1i*Qcar);
Walter Roberson
Walter Roberson el 19 de Mayo de 2020
Looks plausible.

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