How to derive a CDF from a given PDF?
5 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Here is the pdf fucntion: skn = 2.*(1/sqrt(2*pi)).*exp(-0.5*x.^2).*normcdf(a.*x,0,1); How can I define a CDF function from it? Also, after I have CDF, How can I find inverse of that CDF? Thanks.
0 comentarios
Respuestas (1)
Tom Lane
el 9 de Nov. de 2012
If you have the Symbolic Toolbox, you might try replacing normcdf by an erf function and see what you get.
Otherwise you could try something like this:
x = linspace(-5,5);
a = pi;
f = @(x) 2.*(1/sqrt(2*pi)).*exp(-0.5*x.^2).*normcdf(a.*x,0,1);
F = zeros(size(x));
for j=1:length(x)
F(j) = integral(f,-Inf,x(j));
end
plot(x,F)
For the inverse cdf, you might try interpolating or using fzero.
0 comentarios
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!