For loop creating a number sequence

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Erik Börgesson
Erik Börgesson el 25 de Mayo de 2020
Comentada: Rik el 25 de Mayo de 2020
I am not succeeding in creating a loop that creates the number sequence I want.
The following sequence you see is in matlab one single row. It is telling how to traverse in a 13 x 3 table that I have. What the picture is telling you, from the first row: The first column in the first row, the first column in the second row, ... , the first column in the 13:th row. Then, we have the next combination: The first column of the first row, the first column in the second row, ... , the second column in the 13:th column. It will be 1594323 (13^3) different of these, i.e the last one will be: The 13:th column of the first row, the 13:th column in the second row, ... , the 13:th column in the 13 row.
So, I need a (perhaps) for-loop that will create this sequence for me. If anyone nows how to do this, I would really appriciate the help.
  1 comentario
Rik
Rik el 25 de Mayo de 2020
This is not possible. You could generate each in a for-loop, but it is not possible to create that array:
A=ones(13^13,13);
%return:
Error using ones
Requested array exceeds the maximum possible variable size.
Error in Untitled (line 22)
A=ones(13^13,13);
More information
(this assumes you want all permutations of 1:13)

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