Precision problem in log()

Hello! I am using MATLAB for calculating Lyapynov exponent for dynamical system. I need a very hight precision for this calculations. I use vpa() function: vpa('log(some_value_in_my_precision)',my_precision ); my_precision = 5000 or it can be more. Mean it's that a logarithm will be calculated with this precision? Is it possible to calculate the logarithm with hight precision? Thanks.

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the cyclist
the cyclist el 13 de Abr. de 2011

0 votos

I have not used the symbolic math toolbox myself, but according to this page:
vpa will accept the second argument as large as 2^29+1.

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el 13 de Abr. de 2011

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