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Question regarding impoly restraint to move about a specified path

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Lets say I have an implicit equation in x and y f(x,y)=x^2 + y^2 -5*x +12*y +24 which is an example. I construct an impoly with three or n number of vertices over the curve.My question is how can I restrict the movement of vertices of impoly to be restricted to follow the path of the curve.
  2 comentarios
darova
darova el 12 de Jun. de 2020
PLease attach some example or something
Saikat Banerjee
Saikat Banerjee el 12 de Jun. de 2020
I have already attached example. Read question carefully. Let us say we construct a circle through fimplicit(x^2 + y^2 -5*x +12*y +24). After that we construct a traingle with three vertices using impoly. Now the vertices of the triangle will only move along the Circle. Restrain the movement of vertices using impoly along the circle. It will not go inside the circle or can come out of the circle. It will only move on the curve of the Circle

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Respuesta aceptada

darova
darova el 13 de Jun. de 2020
Use setPositionConstraintFcn function
function main
clc,clear
x = 0:.05:10;
y = sin(x);
plot(x,y,'.-r')
h = impoly(gca,[0:2; sin(0:2)]'); % create impoly on the curve
setPositionConstraintFcn(h,@fcn) % assign constraint
function newPos = fcn(currPos)
d = pdist2([x(:) y(:)],currPos);
[~,ix] = min(d); % find closest points
newPos = [x(ix); y(ix)]'; % constrained position
end
end

Más respuestas (1)

Ameer Hamza
Ameer Hamza el 12 de Jun. de 2020
You can use fimplicit() to get the points on the equation and then pass those points to impoly()
f = @(x, y) x.^2 + y.^2 - 5*x + 12*y + 24;
fi = fimplicit(f, [-3 8 -15 0]);
x = fi.XData;
y = fi.YData;
  2 comentarios
Saikat Banerjee
Saikat Banerjee el 13 de Jun. de 2020
I construct impoly as h=impoly([-1,-5];[3,-1];[5,-8]); Now give the rest of the code. I can't understand
Saikat Banerjee
Saikat Banerjee el 14 de Jun. de 2020
This answer is also of help but the other one is better

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