This simple code note working, HELP

%this works well upto t==0.7, but not after 0.8
%give me an answer for this, not links
t=0;
for n=1:10
    t=t+0.1;
    disp(t)
    if t==0.8
        disp('if')
    else
        disp('else')
    end
end

Answer 1

[Ameer Hamza]

Direct comparison using == of floating-point number does not give the correct result. You need to allow some level of tolerance. Try this

t=0;
for n=1:10
    t=t+0.1;
    disp(t);
    if abs(t-0.8) < 1e-6
        disp('if')
    else
        disp('else')
    end
end

[Poojitha Ariyathilaka]

Thank you very much, that worked!

If the case comprises with the floating point, can't we do it by rounding?

t=0;
for n=1:10
    t=round(t+0.1,1);
    disp(t)
    if t==0.8
        disp('if')
    else
        disp('else')
    end
end

[Ameer Hamza]

yes, that will work as well, but it is good to use the tolerance method. Otherwise, you will need to do rounding every time you do some mathematical operation on the variable.

[Poojitha Ariyathilaka]

Yes, tolerance method is much quicker.