Solve for intercepts in nonlinear eq

I have these equations and need to solve them in matrix form and find the two intercepts. i was able to do this with linear eq but cant figure it out with nonlinear. my equations are y = 4 - ((x^2)/2) and y/2 = log10(x+8)

3 comentarios

madhan ravi
madhan ravi el 19 de Jun. de 2020
Hmm nice , knew you would do this. Why waste others time ?
Ameer Hamza
Ameer Hamza el 19 de Jun. de 2020
Original Question:
Title: Solve for intercepts in nonlinear eq
Text: I have these equations and need to solve them in matrix form and find the two intercepts. i was able to do this with linear eq but cant figure it out with nonlinear. my equations are y = 4 - ((x^2)/2) and y/2 = log10(x+8)
Rena Berman
Rena Berman el 12 de Oct. de 2020
(Answers Dev) Restored edit

Iniciar sesión para comentar.

Respuestas (2)

Ameer Hamza
Ameer Hamza el 19 de Jun. de 2020
This equation does not have a closed-form solution. Therefore, you can solve it using fsolve() or vpssolve() if you have symbolic toolbox since this equation has two solutions. The following code shows a way to get both roots by manually specifying a good initial guess.
syms x y
eq1 = y == 4 - ((x^2)/2);
eq2 = y/2 == log10(x+8);
y1 = solve(eq1, y);
y2 = solve(eq2, y);
eq = y1 == y2;
sol1 = vpasolve(eq, 2)
sol2 = vpasolve(eq, -2)

4 comentarios

Sarah Smith
Sarah Smith el 19 de Jun. de 2020
Thank you!! do you know how i would do this if i wanted to solve for the intersection of the those equaitions but also y = x and y = (x+2)/2? So 4 equations total for a the solution
If the solution of four equations exist, the it can be find using following code
syms x y
y1 = 4 - ((x^2)/2);
y2 = 2*log10(x+8);
y3 = x;
y4 = (x+2)/2;
y_sol = vpasolve(std([y1 y2 y3 y4]))
Sarah Smith
Sarah Smith el 19 de Jun. de 2020
I get the error "Empty sym: 0-by-1"
Which MATLAB release are you using. The symbolic toolbox with R2020a is able to give a solution (y_sol=2). Alternatively, you can try a numerical solver
syms x y
y1 = 4 - ((x^2)/2);
y2 = 2*log10(x+8);
y3 = x;
y4 = (x+2)/2;
y = std([y1 y2 y3 y4]);
fun = matlabFunction(y);
y_sol = fsolve(fun, 0);

Iniciar sesión para comentar.

Nipun Agarwal
Nipun Agarwal el 19 de Jun. de 2020

0 votos

Hey,
You cannot solve Non-linear equations with the Matrix form. Matrix form can be used to solve linear equations only. You need to write your own solver or if you have MATRIX Optimization toolbox installed then you can do it with the help of fsolve. Refer this link for more info on fsolve and its applications.

Categorías

Preguntada:

el 19 de Jun. de 2020

Comentada:

el 12 de Oct. de 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by