Switch Case statements MATLAB code in a 'for' loop
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Tahmid Abdullah
el 22 de Jun. de 2020
Respondida: Steven Lord
el 22 de Jun. de 2020
I tried running this code below but I am not getting the output as an array of k but instead the otherwise disp'Code not running') is displayed for 4 times. I don't understand where I'm going wrong or is this method wrong? Any help or advise would be appreciated
Code:
L=[6 7 8 9 10];
k=[];
for i=1:length(L)
switch L(i)
case (L(i)<8)
k(i)= -3;
break;
case (L(i)>8)
k(i)=4;
break;
otherwise
disp('Code not running');
end
end
Output:
Code not running
Code not running
Code not running
Code not running
Code not running
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Respuesta aceptada
Steven Lord
el 22 de Jun. de 2020
switch / case isn't the right tool to use here. I suggest using if / elseif / else instead.
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