Transpose a structure with named fields ?

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I have a struct that looks like this:
i.g. labeled fields
I have been trying to apply this example:
% Fake data
s(1).f = rand(1,100);
s(2).f = rand(1,100);
s(3).f = rand(1,100);
c = arrayfun(@(x)x.f.', s, 'UniformOutput', 0);
s = cell2struct(c, 'f');
but I think it doesn't work becuase I have labeled feilds.
Any ideas?
  1 Comment
Stephen23
Stephen23 on 24 Jun 2020
Edited: Stephen23 on 24 Jun 2020
"Any ideas?"
Your screenshot shows a scalar structure with multiple fields.
Your example code has a non-scalar structure with one field.
It is not clear how that example would apply to the scalar structure shown in your screenshot.
You could use structfun like Mehmed Saad showed, or simply loop over the fieldnames:

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Accepted Answer

Mehmed Saad
Mehmed Saad on 24 Jun 2020
if all of them are scalar then this will work
s_mod=structfun(@transpose,s,'UniformOutput',false)

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