Find a row with all elements satisfying a condition

I have a matrix that looks something like this:

mat = [20, 3; 43 0; 8 3; 100 3; 3 9];

I want to find the rows of the matrix that all of its elements are satisfying a certain condition. For example, if the condition is:

> 10

The result matrix will be:

[8 3; 3 9];

Because those are the only rows in the matrix that both of their elements are smaller then 10. Is there an easy way to achieve this result? Thanks!

Answer 1

[Rasul Khan]

You can achieve it with a loop. The required matrix will be stored in res

res = []
for i = 1 : size(mat , 1)
    if ~any( mat(i , :) > 10  )  % check for the condition , here if any element is > 10, discard the row
        res = [res ; mat(i , :)];
    end
end

[mariajose gomez]

Thanks!!

Answer 2

[darova]

Use logical indexing

mat = [20, 3; 43 0; 8 3; 100 3; 3 9]
ix = sum(mat<10,2)>1;
a1 = mat(ix,:)