Is it possible to rewrite these equation set to matrix form?

3 visualizaciones (últimos 30 días)
I am dealing with some equation set to calculate coefficients b. The equation set is as below. The x y z are the inputs. b is output.
syms x [4 1]
syms y [4 1]
syms z [4 1]
b = zeros(4,1);
b(1) = y3*z2 - y2*z3 + y2*z4 - y4*z2 - y3*z4 + y4*z3;
b(2) = y1*z3 - y3*z1 - y1*z4 + y4*z1 + y3*z4 - y4*z3;
b(3) = y2*z1 - y1*z2 + y1*z4 - y4*z1 - y2*z4 + y4*z2;
b(4) = y1*z2 - y2*z1 - y1*z3 + y3*z1 + y2*z3 - y3*z2;
The equation set would be calculation many times. It takes long time. I want to speed it up. I would like to rewrite this equation set into matrix multiplication, like b = A*[x,y,z] . So I could calculate the vector b in one time , not 4 times. Is it possible? I think this may need some math mind, I have not figure it out. Please help me.
I also try to use subs function. But it is very slow.

Respuesta aceptada

Ameer Hamza
Ameer Hamza el 26 de Jun. de 2020
These variables are nonlinearly related, so not sure how do you want to write in matrix form. Also, it is unlikely that it will cause a significant improvement in speed. You are using a symbolic toolbox that is inherently slow as compared to finite-precision floating-point maths. If you know the values of x, y, and z and want to find values of b, then I suggest you use regular MATLAB operators. For example
syms x [4 1]
syms y [4 1]
syms z [4 1]
b = sym(zeros(4,1));
b(1) = y3*z2 - y2*z3 + y2*z4 - y4*z2 - y3*z4 + y4*z3;
b(2) = y1*z3 - y3*z1 - y1*z4 + y4*z1 + y3*z4 - y4*z3;
b(3) = y2*z1 - y1*z2 + y1*z4 - y4*z1 - y2*z4 + y4*z2;
b(4) = y1*z2 - y2*z1 - y1*z3 + y3*z1 + y2*z3 - y3*z2;
b_fun = matlabFunction(b, 'Vars', {[x1 x2 x3 x4], [y1 y2 y3 y4], [z1 z2 z3 z4]});
x_vec = rand(1,4);
y_vec = rand(1,4);
z_vec = rand(1,4);
b_val = b_fun(x_vec, y_vec, z_vec)

Más respuestas (0)

Categorías

Más información sobre Symbolic Math Toolbox en Help Center y File Exchange.

Productos


Versión

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by